Sql 尽管使用了别名，但从内部查询中找不到列

我是SQL新手，我想从我的查询中导出一个四分位图。然而，我的查询遇到了一些问题

我已经给出了别名，我正在尝试计算四分位数

这是一个问题

SELECT series,
       MIN(value) AS minimum,
       AVG(q1) AS q1,
       AVG(median) AS median,
       AVG(q3) AS q3,
       MAX(value) AS maximum
FROM 
    (SELECT series,
            PERCENTILE_CONT(0.25) WITHIN GROUP 
                 (ORDER BY value) OVER (PARTITION BY series) AS q1,
            MEDIAN(value) OVER (PARTITION BY series) AS median,
            PERCENTILE_CONT(0.75) WITHIN GROUP 
                 (ORDER BY value) OVER (PARTITION BY series) AS q3
     FROM  
         (SELECT type as series, (a.duration)/(60000) as value
          FROM test.pattern a
          JOIN test.metadata b ON a.id = b.id) AS quartile) AS raw_data
GROUP BY 1

然而，我不断地

column "value" does not exist in raw_data

我的列名没有大写字母，这让我现在很困惑

我会很感激你的帮助

更新： 多亏了戈尔丹，查询工作才得以进行。但是，对于大型数据集，执行时间非常慢，是否有关于如何改进的建议

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谢谢

你也需要在中间子查询中选择它：

FROM (SELECT series, value,
---------------------^
             PERCENTILE_CONT(0.25) WITHIN GROUP (ORDER BY value) OVER (PARTITION BY series) AS q1,
             MEDIAN(value) OVER (PARTITION BY series) AS median,
             PERCENTILE_CONT(0.75) WITHIN GROUP (ORDER BY value) OVER (PARTITION BY series) AS q3
      FROM (SELECT type as series, (a.duration)/(60000) as value
                FROM test.pattern p JOIN
                     test.metadata m
                     ON p.id = m.id
          ) AS quartile
     ) AS raw_data

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非常感谢。我让它工作了。然而，这个查询需要很长时间。任何我可以改进的指针performance@YogeshSingh . . . 你应该问另一个关于性能的问题。确保包含查询，解释它在做什么，并提供有关表的大小和索引信息。