Sql 查找给定日期之间的月份

可能重复：

我需要带来结果，两个日期之间的月份是多少

假设日期是

Declare @FrDate datetime,@ToDate datetime
Set @FrDate ='2010-05-31 17:38:58.577' 
Set @ToDate ='2010-09-01 17:38:58.577'

需要输出

Result
MAY
JUN
JUL
AUG
SEP

试试这个：

DECLARE @FrDate  DATETIME,
        @ToDate    DATETIME;

Set @FrDate ='2010-05-31 17:38:58.577' 
Set @ToDate ='2010-09-01 17:38:58.577'

;WITH MONTHS (date)
AS
(
    SELECT @FrDate
    UNION ALL
    SELECT DATEADD(month,1,date)
    from months
    where date<=@ToDate
)
SELECT Datename(month,date) AS MONTH FROM MONTHS

要在结果中获取短月份名称，可以使用以下行：

SELECT LEFT(CONVERT(VARCHAR,date,100),3) AS MONTH FROM MONTHS

要获取大写月份名称，您可以使用

UPPER

函数：

SELECT UPPER(LEFT(CONVERT(VARCHAR,date,100),3)) AS MONTH FROM MONTHS

创建一个，然后您可以简单地编写以下内容：

select distinct MonthName
from dbo.Calendar
where BaseDate between @StartDate and @EndDate

另一种方法

Declare @FrDate datetime,@ToDate datetime 
Set @FrDate ='2010-05-31 17:38:58.577'  
Set @ToDate ='2010-09-01 17:38:58.577' 

select 
    datename(month,dateadd(month,number-1,@FrDate)) as month_name
from 
    master..spt_values 
where 
    type='p'and number between 1 and datediff(month,@frdate,@todate)+1

---

日期维度表可以简化此问题。。。

Declare @FrDate datetime,@ToDate datetime 
Set @FrDate ='2010-05-31 17:38:58.577'  
Set @ToDate ='2010-09-01 17:38:58.577' 

select 
    datename(month,dateadd(month,number-1,@FrDate)) as month_name
from 
    master..spt_values 
where 
    type='p'and number between 1 and datediff(month,@frdate,@todate)+1