Sql Arel连接子查询
我是Rails和Arel的新手 我创建了一个连接查询,但看起来写得很糟糕Sql Arel连接子查询,sql,ruby-on-rails,join,arel,Sql,Ruby On Rails,Join,Arel,我是Rails和Arel的新手 我创建了一个连接查询,但看起来写得很糟糕 join_query = ActiveRecord::Base.connection.execute <<~SQL.strip_heredoc ( SELECT schools.name, sum(q.enrollment), count(*) FROM schools LEFT JOIN ( SELECT sites.s
join_query =
ActiveRecord::Base.connection.execute <<~SQL.strip_heredoc
(
SELECT schools.name, sum(q.enrollment), count(*) FROM schools LEFT JOIN
(
SELECT sites.school_id, sites.enrollment FROM sites JOIN projects ON
sites.project_id = projects.id
WHERE sites.school_id IS NOT NULL and projects.type IN ('Startup') AND projects.deleted_at IS NULL
) q
ON q.school_id = schools.id
GROUP BY schools.name
)
SQL
join_query.values
join\u查询=
ActiveRecord::Base.connection.execute这就是我能想到的给定SQL:
schools = Arel::Table.new("schools")
sites = Arel::Table.new("sites")
projects = Arel::Table.new("projects")
join = sites.project(:school_id, :enrollment)
.join(projects).on(sites[:project_id].eq(projects[:id]))
.where(
sites[:school_id].not_eq(nil)
.and(projects[:type].in("Startup"))
.and(projects[:deleted_at].eq(nil))
)
q = Arel::Table.new(join).alias(:q)
schools.project(:name, q[:enrollment].sum, Arel.star.count)
.join(join, Arel::Nodes::OuterJoin).on(q[:school_id].eq(schools[:id]))
.group(schools[:name])
作为一名新手,以下是我经常访问的一些参考资料:
(官方文件)
(非常有用的备忘单,但不完整)
(左外连接示例)
(Arel综合指南)太棒了!多亏了你,我终于成功了。别名起了作用。我从所学的东西中得出要点