Sql 如何在红移中执行此查询？

对于每个

site\u id

，我必须确定

plan\u id

是否在过去是

1

（过去表示较小的

id

），并且在此之前的某个点不是

1

，例如：

create table billing (id int, site_id int, plan_id int);

insert into billing values
(40301, 1, 1), (40302, 1, 16), (40304, 1, 15),
(40401, 2, 1), (40402, 2, 16), (40403, 2, 1), (40404, 2, 15);

应返回：

site_id = 1, did_return = false
site_id = 2, did_return = true

给定的

站点id

的

计费记录数可以是1个或几十个

我尝试过嵌套查询：

select (
   select (
      select id from billing where plan_id <> 1 and id < b2.id order by id desc limit 1
   )
   from billing b2 where plan_id = 1 and id < b1.id order by id desc limit 1
)
from billing b1
order by id desc limit 1

还有别的办法吗？Redshift与Postgres类似，因此Postgres也可能对此给出答案。
我找到了连接的解决方案：

select b1.site_id, min(b3.id)
from billing b1
left join billing b2 on (b2.id < b1.id and b1.site_id = b2.site_id and b2.plan_id = 1)
left join billing b3 on (b3.id < b2.id and b2.site_id = b3.site_id and b3.plan_id <> 1)
group by b1.site_id

选择b1.site\u id，min（b3.id）
来自账单b1
左连接计费b2打开（b2.id

select b1.site_id, min(b3.id)
from billing b1
left join billing b2 on (b2.id < b1.id and b1.site_id = b2.site_id and b2.plan_id = 1)
left join billing b3 on (b3.id < b2.id and b2.site_id = b3.site_id and b3.plan_id <> 1)
group by b1.site_id