Sql 如何获取使用子查询返回的列值的计数？

我想获取STAGING_CUST_acct表的acct_key列中不存在的所有hrc_acct_num。最后一个外部选择列抛出错误。如何获取使用子查询返回的列的计数

SELECT source_sys_cd, 
       Count(CASE 
               WHEN is_delete = 0 THEN 1 
             END) [DEL IS 0], 
       Sum(CASE 
             WHEN trans_amt = 0 THEN 1 
             ELSE 0 
           END)   [STG $0 TXN CNT], 
       Count(CASE 
               WHEN hrc_acct_num NOT IN(SELECT DISTINCT acct_key 
                                        FROM   staging_cust_acct) THEN 
               hrc_acct_num 
             END) 
FROM   staging_transactions (nolock) 
GROUP  BY source_sys_cd 
ORDER  BY source_sys_cd  

---

可以对子查询执行左联接，然后在值为null时执行求和。会计键

SELECT source_sys_cd, 
       Count(CASE 
               WHEN is_delete = 0 THEN 1 
             END) [DEL IS 0], 
       Sum(CASE 
             WHEN trans_amt = 0 THEN 1 
             ELSE 0 
           END)   [STG $0 TXN CNT], 
       SUM(CASE WHEN T.acct_key is NULL THEN 1 else 0  END ) CountNotIN

FROM   staging_transactions (nolock) s
       LEFT JOIN (SELECT DISTINCT acct_key 
                                        FROM   staging_cust_acct) t 
        s.hrc_acct_num  = t.acct_key 
GROUP  BY source_sys_cd 
ORDER  BY source_sys_cd  

---

您可以使用“不存在”短接子查询。它比LEFT-JOIN-SELECT-DISTINCT更有效，因为您不关心枚举它存在的所有时间

   SELECT source_sys_cd, 
           Count(CASE is_delete WHEN 
                   WHEN is_delete = 0 THEN 1 
                 END) [DEL IS 0], 
           Count(CASE 
                   WHEN trans_amt = 0 THEN 1 
                 END) [STG $0 TXN CNT], 
           Count(CASE 
                   WHEN NOT EXISTS (SELECT 1
                                    FROM staging_cust_acct
                                    WHERE acct_key = hrc_acct_num) THEN 1
                 END) 
    FROM   staging_transactions (nolock)
    GROUP  BY source_sys_cd 
    ORDER  BY source_sys_cd  

---

Sum在这种情况下也会起作用，但是，count不会增加null值，如果条件不为true，则会从case语句返回null值。在这种情况下，@JaazCole您是对的。出于某种原因，我在那里读到了另一个0。个人