Oracle SQL>&燃气轮机；同一表中父、子和孙的分层查询

我的表中有如下结构的数据

Manager Id  Employee id chartfield
SM1           MGR-1        12
SM2           MGR-1        12
MGR-1         LEAD-1       12
MGR-1         LEAD-2       12
MGR-1         LEAD-3       12
LEAD-1        LEAD-2       12
LEAD-1      ASSOCIATE -1    12
LEAD-1      ASSOCIATE -2    12
LEAD-2       LEAD-3         12
LEAD-2      ASSOCIATE -3    12
LEAD-2      ASSOCIATE -4    12
LEAD-3      ASSOCIATE -5    12
LEAD-3      ASSOCIATE -6    12
ASSOCIATE -1    JUNIOR - 1  12
ASSOCIATE -1    JUNIOR - 2  12
ASSOCIATE -2    JUNIOR - 1  12
ASSOCIATE -2    JUNIOR - 2  12

Manager Id  Employee id chartfield  LEVEL1
MGR-1   LEAD-1           12           1
MGR-1   LEAD-2           12           1
MGR-1   LEAD-3           12           1
MGR-1   ASSOCIATE -1    12            2
MGR-1   ASSOCIATE -2    12            2
MGR-1   ASSOCIATE -3    12            2
MGR-1   ASSOCIATE -4    12            2
MGR-1   ASSOCIATE -5    12            2
MGR-1   ASSOCIATE -6    12            2
MGR-1   JUNIOR - 1      12            3
MGR-1   JUNIOR - 2      12            3

我期望经理和员工的产出与他们目前的水平一致。这里唯一的标准是同一个员工可以向多个经理报告，在这种情况下，我们应该只选择向级别最低的员工报告的不同员工。在上述情况下，2号领导向1号经理和1号领导报告，但我们正在考虑最低级别

示例输出可能如下所示：

Manager Id  Employee id chartfield
SM1           MGR-1        12
SM2           MGR-1        12
MGR-1         LEAD-1       12
MGR-1         LEAD-2       12
MGR-1         LEAD-3       12
LEAD-1        LEAD-2       12
LEAD-1      ASSOCIATE -1    12
LEAD-1      ASSOCIATE -2    12
LEAD-2       LEAD-3         12
LEAD-2      ASSOCIATE -3    12
LEAD-2      ASSOCIATE -4    12
LEAD-3      ASSOCIATE -5    12
LEAD-3      ASSOCIATE -6    12
ASSOCIATE -1    JUNIOR - 1  12
ASSOCIATE -1    JUNIOR - 2  12
ASSOCIATE -2    JUNIOR - 1  12
ASSOCIATE -2    JUNIOR - 2  12

Manager Id  Employee id chartfield  LEVEL1
MGR-1   LEAD-1           12           1
MGR-1   LEAD-2           12           1
MGR-1   LEAD-3           12           1
MGR-1   ASSOCIATE -1    12            2
MGR-1   ASSOCIATE -2    12            2
MGR-1   ASSOCIATE -3    12            2
MGR-1   ASSOCIATE -4    12            2
MGR-1   ASSOCIATE -5    12            2
MGR-1   ASSOCIATE -6    12            2
MGR-1   JUNIOR - 1      12            3
MGR-1   JUNIOR - 2      12            3

---

您的示例数据显示每个人都向SM1和SM2报告。。。无论如何，假设应该正确处理重复的管理器，即只应选择一个，那么下面的查询如何：

WITH t (
  MANAGER_ID,
  EMPLOYEE_ID,
  LEVEL_NUM
) AS (
  SELECT
    e.MANAGER_ID,
    e.MANAGER_ID,
    0 AS LEVEL_NUM
  FROM
    emp e
  WHERE
    e.MANAGER_ID NOT IN (
      SELECT
        e.EMPLOYEE_ID
      FROM
        emp e
      )
  UNION ALL
    SELECT
      t.MANAGER_ID,
      e.EMPLOYEE_ID,
      t.LEVEL_NUM + 1 AS LEVEL_NUM      
    FROM
      emp e
    JOIN
      t
    ON
      e.MANAGER_ID = t.EMPLOYEE_ID
)
SELECT
  MANAGER_ID,
  EMPLOYEE_ID,
  LEVEL_NUM
FROM
  (
    SELECT
      MANAGER_ID,
      EMPLOYEE_ID,
      LEVEL_NUM,
      ROW_NUMBER() OVER (PARTITION BY EMPLOYEE_ID ORDER BY LEVEL_NUM, MANAGER_ID) AS ROW_NUM
    FROM
      t
  ) t
WHERE
  t.ROW_NUM = 1 -- keep only the first manager
AND
  t.LEVEL_NUM > 0  -- exclude top level managers reporting to themselves
ORDER BY
  t.LEVEL_NUM,
  t.MANAGER_ID,
  t.EMPLOYEE_ID;

以及用于处理数据周期的查询：

WITH t (
  MANAGER_ID,
  EMPLOYEE_ID,
  PATH,
  LEVEL_NUM
) AS (
  SELECT
    e.MANAGER_ID,
    e.MANAGER_ID,
    '> ' || e.MANAGER_ID AS PATH,
    0 AS LEVEL_NUM
  FROM
    emp e
  UNION ALL
    SELECT
      t.MANAGER_ID,
      e.EMPLOYEE_ID,
      t.PATH || ' > ' || e.EMPLOYEE_ID AS PATH,
      t.LEVEL_NUM + 1 AS LEVEL_NUM
    FROM
      emp e
    JOIN
      t
    ON
      e.MANAGER_ID = t.EMPLOYEE_ID
    WHERE
     t.PATH NOT LIKE '%> ' || e.EMPLOYEE_ID || '%'
)
SELECT
  t.MANAGER_ID,
  t.EMPLOYEE_ID,
  t.LEVEL_NUM
FROM
  (
    SELECT
      t.MANAGER_ID,
      t.EMPLOYEE_ID,
      t.LEVEL_NUM,
      ROW_NUMBER() OVER (PARTITION BY t.MANAGER_ID, t.EMPLOYEE_ID ORDER BY t.LEVEL_NUM) AS ROW_NUM
    FROM
      t
  ) t
WHERE
  t.ROW_NUM = 1 -- keep only the first employee occurance
AND
  t.LEVEL_NUM > 0  -- exclude top level managers reporting to themselves
AND
  t.MANAGER_ID = 'SM1'  -- selected manager
ORDER BY
  t.LEVEL_NUM,
  t.MANAGER_ID,
  t.EMPLOYEE_ID;

---

请仅使用相关产品标签，或者MGR-1如何向SM1和SM2报告（两者似乎处于同一级别）？这两条记录应该保留在输出中还是只保留一条？古格利：你在7小时前回答了一个问题（在我写这篇评论的时候）。12小时前，同一位论坛成员miazo向您提出了上述问题。你来到这里，你回答了他的回答，但没有回答上面的问题。为什么不呢？这是一个非常重要的问题，非常有意义，您需要回答它，否则任何人都无法为您的问题提供一个好的解决方案。在运行时，我会将经理id指定为“MGR-1”，以便将所有潜在客户、员工和下级报告提供给他。但是上面的sql给出了循环冗余错误。如果您得到了一个循环错误，那么您的测试数据中就有了循环（不是这里发布的示例数据，第一个查询就可以在它上面运行）。我添加了另一个查询来处理这个问题，请检查这是否解决了您的问题。