Sql 合并联合结果

我有下面的SQL查询

  select Count(emailID) as ViewsThatMonth, 
         Day(entry_date) as day, 
         Month(entry_date) as month, 
         Year(entry_date) as year 
    from email_views
   where emailID = 110197
Group By Day(entry_date), Month(entry_date), Year(entry_date)
UNION ALL 
  select Count(emailID) as ViewsThatMonth, 
         Day(Record_Entry) as day, 
         Month(Record_Entry) as month, 
         Year(Record_Entry) as year 
    from dbo.tblOnlineEmail_Views
   where emailID = 110197
Group By Day(Record_Entry), Month(Record_Entry), Year(Record_Entry)
order by 4, 3, 2

结果如下所示。我需要把同一天的结果合并起来。即，2010年8月23日的总数应为800

ViewsThatMonth  day  month  year 
---------------------------------
799             23   8      2010
1               23   8      2010
281             24   8      2010
88              25   8      2010
1               25   8      2010

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基本上最简单的方法是将您的union设置为派生表或CTE，然后按日期对它们进行分组

即

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将联合代码保持在最低限度：

select Count(emailID) as ViewsThatMonth, 
         Day(sort_date) as day, 
         Month(sort_date) as month, 
         Year(sort_date) as year 
    from (select v.*, 
          case c.caseid when 1 then entry_date else record_entry end sort_date
          from email_views v
          cross join (select 1 caseid union all select 2 caseid) c
          where v.emailID = 110197) sq
Group By Day(sort_date), Month(sort_date), Year(sort_date)

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编辑：将别名添加到子查询中

您只需按一次分组：

SELECT Count(emailID) as ViewsThatMonth, 
         Day(entry_date) as day, 
         Month(entry_date) as month, 
         Year(entry_date) as year
from(
select emailID, Record_Entry AS entry_date 
    from email_views
   where emailID = 110197
UNION ALL 
  select emailID, entry_date 
    from dbo.tblOnlineEmail_Views
   where emailID = 110197
) AS t
Group By Day(entry_date), Month(entry_date), Year(entry_date)
order by 4, 3, 2

Count（Record\u Entry）

应该是

Count（emailId）

我想。谢谢，但是我得到了一个“关键字'Group'附近语法不正确”的错误

SELECT Count(emailID) as ViewsThatMonth, 
         Day(entry_date) as day, 
         Month(entry_date) as month, 
         Year(entry_date) as year
from(
select emailID, Record_Entry AS entry_date 
    from email_views
   where emailID = 110197
UNION ALL 
  select emailID, entry_date 
    from dbo.tblOnlineEmail_Views
   where emailID = 110197
) AS t
Group By Day(entry_date), Month(entry_date), Year(entry_date)
order by 4, 3, 2