SQL查询以查找一系列值的长度

我需要一个查询，用于计算列

FL\u SUCC\u EXEC

中最长的不间断的后续“1”序列。对于表

测试中的以下数据（行编号，fl成功执行编号（1））

，查询结果应为“6”

行按

行编号

排序

    ROW_NO   FL_SUCC_EXEC
---------- ------------
         1            1
         2            1
         3            1
         4            0
         5            1
         6            1
         7            1
         8            1
         9            1
        10            1
        11            0                               
        12            1
        13            1
        14            1  
        15            1  

我可以在PL/SQL中实现这一点：

declare
temp_cnt pls_integer default 0;
total_cnt pls_integer default 0;
begin
for rec in (select row_no, fl_succ_exec from test order by row_no)
loop
  if temp_cnt > total_cnt
   then 
   total_cnt:=temp_cnt;
  end if;

  if rec.fl_succ_exec!=0 
  then
     temp_cnt:=temp_cnt+rec.fl_succ_exec;
  else
     temp_cnt:=0;
  end if;

end loop;
dbms_output.put_line(total_cnt);
end;

---

但我仍然希望SQL解决方案。是否有任何Oracle设置？

CREATE TABLE test ( row_no, fl_succ_exec ) AS
  SELECT  1, 1 FROM DUAL UNION ALL
  SELECT  2, 1 FROM DUAL UNION ALL
  SELECT  3, 1 FROM DUAL UNION ALL
  SELECT  4, 0 FROM DUAL UNION ALL
  SELECT  5, 1 FROM DUAL UNION ALL
  SELECT  6, 1 FROM DUAL UNION ALL
  SELECT  7, 1 FROM DUAL UNION ALL
  SELECT  8, 1 FROM DUAL UNION ALL
  SELECT  9, 1 FROM DUAL UNION ALL
  SELECT 10, 1 FROM DUAL UNION ALL
  SELECT 11, 0 FROM DUAL UNION ALL
  SELECT 12, 1 FROM DUAL UNION ALL
  SELECT 13, 1 FROM DUAL UNION ALL
  SELECT 14, 1 FROM DUAL UNION ALL
  SELECT 15, 1 FROM DUAL;

SELECT MAX( num_1s ) AS num_1s
FROM   (
  SELECT COALESCE(
           row_no - LAST_VALUE( CASE fl_succ_exec WHEN 0 THEN row_no END )
                      IGNORE NULLS OVER ( ORDER BY row_no ),
           ROWNUM
         ) AS num_1s
  FROM   test
);

NUM_1S
------
     6

查询：

CREATE TABLE test ( row_no, fl_succ_exec ) AS
  SELECT  1, 1 FROM DUAL UNION ALL
  SELECT  2, 1 FROM DUAL UNION ALL
  SELECT  3, 1 FROM DUAL UNION ALL
  SELECT  4, 0 FROM DUAL UNION ALL
  SELECT  5, 1 FROM DUAL UNION ALL
  SELECT  6, 1 FROM DUAL UNION ALL
  SELECT  7, 1 FROM DUAL UNION ALL
  SELECT  8, 1 FROM DUAL UNION ALL
  SELECT  9, 1 FROM DUAL UNION ALL
  SELECT 10, 1 FROM DUAL UNION ALL
  SELECT 11, 0 FROM DUAL UNION ALL
  SELECT 12, 1 FROM DUAL UNION ALL
  SELECT 13, 1 FROM DUAL UNION ALL
  SELECT 14, 1 FROM DUAL UNION ALL
  SELECT 15, 1 FROM DUAL;

SELECT MAX( num_1s ) AS num_1s
FROM   (
  SELECT COALESCE(
           row_no - LAST_VALUE( CASE fl_succ_exec WHEN 0 THEN row_no END )
                      IGNORE NULLS OVER ( ORDER BY row_no ),
           ROWNUM
         ) AS num_1s
  FROM   test
);

NUM_1S
------
     6

输出：

CREATE TABLE test ( row_no, fl_succ_exec ) AS
  SELECT  1, 1 FROM DUAL UNION ALL
  SELECT  2, 1 FROM DUAL UNION ALL
  SELECT  3, 1 FROM DUAL UNION ALL
  SELECT  4, 0 FROM DUAL UNION ALL
  SELECT  5, 1 FROM DUAL UNION ALL
  SELECT  6, 1 FROM DUAL UNION ALL
  SELECT  7, 1 FROM DUAL UNION ALL
  SELECT  8, 1 FROM DUAL UNION ALL
  SELECT  9, 1 FROM DUAL UNION ALL
  SELECT 10, 1 FROM DUAL UNION ALL
  SELECT 11, 0 FROM DUAL UNION ALL
  SELECT 12, 1 FROM DUAL UNION ALL
  SELECT 13, 1 FROM DUAL UNION ALL
  SELECT 14, 1 FROM DUAL UNION ALL
  SELECT 15, 1 FROM DUAL;

SELECT MAX( num_1s ) AS num_1s
FROM   (
  SELECT COALESCE(
           row_no - LAST_VALUE( CASE fl_succ_exec WHEN 0 THEN row_no END )
                      IGNORE NULLS OVER ( ORDER BY row_no ),
           ROWNUM
         ) AS num_1s
  FROM   test
);

NUM_1S
------
     6

尝试：