Sql 带条件的聚合？

我试图根据条件if玩家id（Gary）进行聚合 得分高于、等于或低于玩家id（“其他”）

我的模式已更改

players(player_id, name) 

matches(match_id, home_team(player_id), away_team(player_id) )

outcome(outcome_id, match_id, home_score:integer, away_score:integer

输出自：

select m.match_id, p.name AS home_team, p1.name AS away_team, o.home_score, o.away_score
from players p
inner join matches m on (p.player_id = m.home_team)
inner join players p1 on (p1.player_id = m.away_team)
inner join outcomes o on (m.match_id = o.match_id);

 match_id | player_id | player_id | home_score | away_score 
----------+-----------+-----------+------------+------------
        1 | 1         | 2         |          1 |          2
        2 | 2         | 1         |          1 |          3
        3 | 3         | 1         |          3 |          2

想要的输出：

 player_id   | Wins | Draws | Losses
-------------+------+-------+--------
  1          |    1 |    0  |    2
  2    ...   | ...  |    .. |    ...

我的模式可以更改

---

编辑（SQLFIDLE）：

对于没有子查询和联合的解决方案：

---

我会使用

UNION ALL

两次获取每个

结果，一次用于
主场
，一次用于
客场
玩家。第二次
主客场得分
/
客场得分
应切换，以获得客场球员的正确总和

select
  d.player_id,
  d.name, 
  sum(d.home_score > d.away_score) as wins,
  sum(d.home_score = d.away_score) as draws,
  sum(d.home_score < d.away_score) as loses
from (
    select p.player_id, p.name, o.home_score, o.away_score
    from players p
    join matches m on p.player_id = m.home_team
    join outcomes o on o.match_id = m.match_id
  union all
    select p.player_id, p.name, o.away_score as home_score, o.home_score as away_score
    from players p
    join matches m on p.player_id = m.away_team
    join outcomes o on o.match_id = m.match_id) d
group by d.player_id, d.name

sqlFiddle演示：
啊，对于模棱两可的问题，很抱歉，这不重要！重点是获得每个玩家@Filipe SilvaCan的赢、输和平局的数量。您可以使用原始表格样本数据添加一个吗？可以@FilipeSilva@FilipeSilvaThis不会像预期的那样返回结果。我担心，这应该是因为Marcin的answare@wolphindect，我忘记了反向关系：）我添加了一个修改版本。我个人不是工会的粉丝，一切都很好！，感谢您提供的解决方案，我从这两个例子中学到了很多！我也想把你的answare作为解决方案，但marcin“更快地”解决了它，在生产中，我想我会使用你的解决方案，尽管@wolph谢谢！这非常有帮助，并得到了预期的结果，尽管我不知道我的模式是否正确地设置为应答此类查询@马金库拉泽克
PLAYER_ID   WINS    DRAWS   LOSSES
1   1   0   2
2   1   0   1
3   1   0   0
4   0   0   0
5   0   0   0

select
  d.player_id,
  d.name, 
  sum(d.home_score > d.away_score) as wins,
  sum(d.home_score = d.away_score) as draws,
  sum(d.home_score < d.away_score) as loses
from (
    select p.player_id, p.name, o.home_score, o.away_score
    from players p
    join matches m on p.player_id = m.home_team
    join outcomes o on o.match_id = m.match_id
  union all
    select p.player_id, p.name, o.away_score as home_score, o.home_score as away_score
    from players p
    join matches m on p.player_id = m.away_team
    join outcomes o on o.match_id = m.match_id) d
group by d.player_id, d.name

PLAYER_ID   NAME    WINS    DRAWS   LOSES
1           Gary    1       0       2
2           Tom     1       0       1
3           Brad    1       0       0