MS Access中的SQL计数

我有一个名为[Review Results]的表，看起来有点像下面的：

[Reviewed By]....[Review Date]....[Corrective Action]....[CAR]
John.............1/1/2011.........yes....................yes
John.............2/5/2011.........No.....................yes
John.............2/24/2011........yes....................yes
Bobby............1/1/2011.........No.....................No
Bobby............3/1/2011.........yes....................No  

我试图显示审核人在指定时间段内的

[Corrective Action]=yes

数量，以及审核人在指定时间段内的

[CAR]=yes

数量。我尝试使用以下SQL，但它没有给出正确的输出：

select 
[Reviewed By],
Count(IIF([Corrective Action] = yes, 1,0)) as [CAMBRs],
Count(IIF([CAR] = yes,1,0)) as [CARs]

from [Review Results] 

where [Review Date]  between #1/1/2011# and #3/1/2011#

group by
[Reviewed By]  

---

有人能用SQL为我指出正确的方向吗？

可能是这样的：

select 
[Reviewed By],
SUM(IIF([Corrective Action] = "yes", 1,0)) as [CAMBRs],
SUM(IIF([CAR] = "yes",1,0)) as [CARs]

from [Review Results] 

where [Review Date]  between #1/1/2012# and #3/1/2012#

group by
[Reviewed By]  

select 
   [Reviewed By],
   SUM(IIF([Corrective Action] = True, 1,0)) as [CAMBRs],
   SUM(IIF([CAR] = True,1,0)) as [CARs]

from [Review Results] 

where [Review Date]  between #1/1/2012# and #3/1/2012#

group by
[Reviewed By]

---

我应该提到，[Corrective Action]和[CAR]字段是表[Review Results]中的复选框，在这种情况下，您可以使用Abs（[Corrective Action]）返回1或0<代码>计数（Abs（[纠正措施]）您正在计算查询中的所有“否”。。。。