比较SQL Server表中的两条记录并删除不需要的记录
我在表格中有这些数据：比较SQL Server表中的两条记录并删除不需要的记录,sql,sql-server,tsql,Sql,Sql Server,Tsql,我在表格中有这些数据： UID Date Codes Ratecell --------------------------------------- 11111111 01/01/17 021 A111 11111111 01/01/17 024 A111 22222222 01/01/17 021 A112 22222222 01/01/17 024 A111 33333333 01
UID Date Codes Ratecell
---------------------------------------
11111111 01/01/17 021 A111
11111111 01/01/17 024 A111
22222222 01/01/17 021 A112
22222222 01/01/17 024 A111
33333333 01/01/18 001 A112
33333333 01/01/18 021 A112
我的问题是：如果UID上存在匹配项，并且相同日期但代码不同的UID的RateCell相同，则删除代码为024的记录。如何编写或加入查询以实现此目的？我认为窗口功能：
select t.*
from (select t.*,
min(ratecell) over (partition by uid, date, code) as min_ratecell,
max(ratecell) over (partition by uid, date, code) as max_ratecell
from t
) t
where not (min_ratecell <> max_ratecell and ratecell = 'A112');
如果需要，您可以轻松地将其转换为实际删除。我认为窗口功能：
select t.*
from (select t.*,
min(ratecell) over (partition by uid, date, code) as min_ratecell,
max(ratecell) over (partition by uid, date, code) as max_ratecell
from t
) t
where not (min_ratecell <> max_ratecell and ratecell = 'A112');
如果需要，您可以轻松地将其转换为实际删除。公共表表达式CTE对该任务非常有用。参见示例
declare @tbl table(UID int, [Date] Date, Codes varchar(10), Ratecell varchar(10))
insert @tbl values
(11111111, '01/01/17', '021', 'A111'),
(11111111, '01/01/17', '024', 'A111'),
(22222222, '01/01/17', '021', 'A112'),
(22222222, '01/01/17', '024', 'A111'),
(33333333, '01/01/18', '001', 'A112'),
(33333333, '01/01/18', '021', 'A112')
;with cte as (
select *,
ROW_NUMBER() over (partition by uid,[date],ratecell order by codes) rn
from @tbl
)
--select * from cte -- uncomment for test
delete cte --comment for test
where rn > 1
select * from @tbl t
公共表表达式CTE对该任务非常有帮助。参见示例
declare @tbl table(UID int, [Date] Date, Codes varchar(10), Ratecell varchar(10))
insert @tbl values
(11111111, '01/01/17', '021', 'A111'),
(11111111, '01/01/17', '024', 'A111'),
(22222222, '01/01/17', '021', 'A112'),
(22222222, '01/01/17', '024', 'A111'),
(33333333, '01/01/18', '001', 'A112'),
(33333333, '01/01/18', '021', 'A112')
;with cte as (
select *,
ROW_NUMBER() over (partition by uid,[date],ratecell order by codes) rn
from @tbl
)
--select * from cte -- uncomment for test
delete cte --comment for test
where rn > 1
select * from @tbl t
为了建立@Alex Kudryashev和@Gordon Linoff回答的内容，应该删除除代码外所有匹配的记录，并且代码值=到024。这可以通过使用CTE查找重复记录，然后从表中删除这些重复记录来实现
Create table ##temp (
[UID] int, [Date] datetime, [Codes] varchar(10), [Ratecell] varchar(10)
)
insert into ##temp
(
[UID]
,[Date]
,[Codes]
,[Ratecell]
)
values
(11111111, '01/01/17', '021', 'A111'),
(11111111, '01/01/17', '024', 'A111'),
(22222222, '01/01/17', '021', 'A112'),
(22222222, '01/01/17', '024', 'A111'),
(33333333, '01/01/18', '001', 'A112'),
(33333333, '01/01/18', '021', 'A112')
;with cte_ratecell as
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from
##temp
)
select * from ##temp
--Delete c
select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
UID Date Codes Ratecell RN
----------- ----------------------- ---------- ---------- ------
11111111 2017-01-01 00:00:00.000 024 A111 2
Delete c
--select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
UID Date Codes Ratecell RN
----------- ----------------------- ---------- ---------- ------
11111111 2017-01-01 00:00:00.000 024 A111 2
Delete c
--select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
为了建立@Alex Kudryashev和@Gordon Linoff回答的内容，应该删除除代码外所有匹配的记录，并且代码值=到024。这可以通过使用CTE查找重复记录，然后从表中删除这些重复记录来实现
Create table ##temp (
[UID] int, [Date] datetime, [Codes] varchar(10), [Ratecell] varchar(10)
)
insert into ##temp
(
[UID]
,[Date]
,[Codes]
,[Ratecell]
)
values
(11111111, '01/01/17', '021', 'A111'),
(11111111, '01/01/17', '024', 'A111'),
(22222222, '01/01/17', '021', 'A112'),
(22222222, '01/01/17', '024', 'A111'),
(33333333, '01/01/18', '001', 'A112'),
(33333333, '01/01/18', '021', 'A112')
;with cte_ratecell as
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from
##temp
)
select * from ##temp
--Delete c
select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
UID Date Codes Ratecell RN
----------- ----------------------- ---------- ---------- ------
11111111 2017-01-01 00:00:00.000 024 A111 2
Delete c
--select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
UID Date Codes Ratecell RN
----------- ----------------------- ---------- ---------- ------
11111111 2017-01-01 00:00:00.000 024 A111 2
Delete c
--select *
from
(
select
[UID]
,[Date]
,[Codes]
,[Ratecell]
,ROW_NUMBER() over (partition by [UID], [Ratecell], [Date] order by Codes) as RN
from ##temp) c
where
RN > 1 and [Codes] = '024'
要解释你的编辑。。。如果多行共享相同的UID、date、ratecell值，但具有不同的代码值，请删除代码为“024”的所有此类行
由于CTE是如何构建的，它实际上是模式绑定的，这意味着从CTE中删除一行会导致源表中的基础行被删除。要解释您的编辑。。。如果多行共享相同的UID、date、ratecell值，但具有不同的代码值，请删除代码为“024”的所有此类行
由于CTE是如何构建的，它实际上是模式绑定的，这意味着从CTE中删除一行会导致源表中的基础行被删除。Thank@Gordon。我刚刚编辑了我的问题。我需要匹配ratecells并删除代码为024的记录。您能帮忙吗？谢谢@Gordon。我刚刚编辑了我的问题。我需要匹配ratecells并删除codes=024的记录。您是否有机会提供帮助？提示使用适当的软件MySQL、Oracle、DB2等标记数据库问题是很有帮助的。。。和版本，例如sql-server-2014。语法和特性的差异通常会影响答案。。。和版本，例如sql-server-2014。语法和功能的差异通常会影响答案。请投票否决我的答案的人解释他们为什么投票否决我的答案？请投票否决我的答案的人解释他们为什么投票否决我的答案？