将行转换为列SQL Server 2005/8
我刚刚开始深入了解SQL Server,我遇到了一个问题。我必须把一行转换成一列,但我想不出来 该行如下所示:将行转换为列SQL Server 2005/8,sql,sql-server,pivot,unpivot,Sql,Sql Server,Pivot,Unpivot,我刚刚开始深入了解SQL Server,我遇到了一个问题。我必须把一行转换成一列,但我想不出来 该行如下所示: Columns: T1 T2 T3 .........T20 Values: 1 0 9 ......... 15 Col Val ________ T1 1 T2 0 T3 9 ........ T20 15 SELECT col, val FROM Table
Columns: T1 T2 T3 .........T20
Values: 1 0 9 ......... 15
Col Val
________
T1 1
T2 0
T3 9
........
T20 15
SELECT col, val
FROM Tablename AS t
UNPIVOT
(
Val
FOR Col IN (T1, T2, ..., T20)
) AS u;
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
select @cols = STUFF((SELECT distinct ',' +
QUOTENAME(column_name)
FROM information_schema.columns
WHERE table_name = 'tablename'
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
, 1, 1, '');
SELECT @query = ' SELECT col, val
FROM tablename AS t
UNPIVOT
(
val
FOR col IN ( ' + @cols + ' )
) AS u;';
EXECUTE(@query);
我想收到这样的东西:
Columns: T1 T2 T3 .........T20
Values: 1 0 9 ......... 15
Col Val
________
T1 1
T2 0
T3 9
........
T20 15
SELECT col, val
FROM Tablename AS t
UNPIVOT
(
Val
FOR Col IN (T1, T2, ..., T20)
) AS u;
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
select @cols = STUFF((SELECT distinct ',' +
QUOTENAME(column_name)
FROM information_schema.columns
WHERE table_name = 'tablename'
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
, 1, 1, '');
SELECT @query = ' SELECT col, val
FROM tablename AS t
UNPIVOT
(
val
FOR col IN ( ' + @cols + ' )
) AS u;';
EXECUTE(@query);
我知道我必须使用枢轴,我已经读过这方面的内容,但我想不出它是什么您必须使用表运算符来实现这一点,如下所示:
Columns: T1 T2 T3 .........T20
Values: 1 0 9 ......... 15
Col Val
________
T1 1
T2 0
T3 9
........
T20 15
SELECT col, val
FROM Tablename AS t
UNPIVOT
(
Val
FOR Col IN (T1, T2, ..., T20)
) AS u;
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
select @cols = STUFF((SELECT distinct ',' +
QUOTENAME(column_name)
FROM information_schema.columns
WHERE table_name = 'tablename'
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
, 1, 1, '');
SELECT @query = ' SELECT col, val
FROM tablename AS t
UNPIVOT
(
val
FOR col IN ( ' + @cols + ' )
) AS u;';
EXECUTE(@query);
更新1 如果您想对任意数量的列动态执行此操作,而不需要手动写入,我唯一能想到的方法是从表
信息\u schema.columns
中读取这些列,以获取表的列名称列表。然后使用动态SQL动态地为col IN…编写语句,如下所示:
Columns: T1 T2 T3 .........T20
Values: 1 0 9 ......... 15
Col Val
________
T1 1
T2 0
T3 9
........
T20 15
SELECT col, val
FROM Tablename AS t
UNPIVOT
(
Val
FOR Col IN (T1, T2, ..., T20)
) AS u;
DECLARE @cols AS NVARCHAR(MAX);
DECLARE @query AS NVARCHAR(MAX);
select @cols = STUFF((SELECT distinct ',' +
QUOTENAME(column_name)
FROM information_schema.columns
WHERE table_name = 'tablename'
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
, 1, 1, '');
SELECT @query = ' SELECT col, val
FROM tablename AS t
UNPIVOT
(
val
FOR col IN ( ' + @cols + ' )
) AS u;';
EXECUTE(@query);
这将为您提供:
| COL | VAL |
-------------
| T1 | 1 |
| T10 | 15 |
| T11 | 33 |
| T12 | 31 |
| T13 | 12 |
| T14 | 10 |
| T15 | 12 |
| T16 | 9 |
| T17 | 10 |
| T18 | 2 |
| T19 | 40 |
| T2 | 0 |
| T20 | 21 |
| T3 | 9 |
| T4 | 2 |
| T5 | 3 |
| T6 | 10 |
| T7 | 14 |
| T8 | 15 |
| T9 | 20 |
谢谢马哈茂德·贾马尔。工作起来很有魅力,我有一个开始:)人们必须事先知道要旋转的柱子。我有一个使用临时表和动态查询“发现”它们的解决方案,今天晚些时候我会发布(当我有时间这样做的时候)。我已经给了你+1,但我很高兴你也发布了一个动态版本。:)@蓝脚-谢谢。你是老板:)我刚从你那里学到了所有这些pivot/unpivot的东西。