按连续外键值分组的Sql查询

我有这样的数据：

+----+-------------------------+----------+----------+
| ID |      DateReceived       | Quantity | VendorID |
+----+-------------------------+----------+----------+
|  1 | 2010-08-09 06:53:44.783 |        2 |        1 |
|  2 | 2010-08-01 13:31:26.893 |        1 |        1 |
|  3 | 2010-07-26 07:52:29.403 |        2 |        1 |
|  4 | 2011-03-22 13:31:11.000 |        1 |        2 |
|  5 | 2011-03-22 13:31:11.000 |        1 |        2 |
|  6 | 2011-03-22 11:27:01.000 |        1 |        2 |
|  7 | 2011-03-18 09:04:58.000 |        1 |        1 |
|  8 | 2011-12-17 08:21:29.000 |        1 |        3 |
|  9 | 2012-08-10 10:55:20.000 |        9 |        3 |
| 10 | 2012-08-02 20:18:10.000 |        5 |        1 |
| 11 | 2012-07-12 20:44:36.000 |        3 |        1 |
| 12 | 2012-07-05 20:45:29.000 |        1 |        1 |
| 13 | 2013-03-22 13:31:11.000 |        1 |        2 |
| 14 | 2013-03-22 13:31:11.000 |        1 |        2 |
+----+-------------------------+----------+----------+

我想按

接收日期对数据进行排序

并对

数量

求和。但是，我想对由

VendorID

分组的

数量进行求和，只要它们相邻，就像下面的示例输出一样

+----------+----------+
| VendorID | Quantity |
+----------+----------+
|        1 |        5 |
|        2 |        3 |
|        1 |        1 |
|        3 |       10 |
|        1 |        9 |
|        2 |        2 |
+----------+----------+

我目前正在通过加载所有行并在应用程序代码中遍历它们来实现这一点。这是目前我想消除的软件瓶颈

生成所需输出的MS Sql Server查询是什么

注：对更好的标题有什么建议吗？
在SQL Server 2005+中，您可以执行以下操作：

with cte as (
    select
        VendorID, Quantity,
        row_number() over(partition by VendorID order by DateReceived) as rn1,
        row_number() over(order by DateReceived) as rn2
    from Table1
)
select
    VendorID, sum(Quantity) as Quantity
from cte 
group by VendorID, rn2 - rn1
order by min(rn2)


在SQL Server 2012中，可以使用lag（）函数：

with cte as (
    select
        VendorID, Quantity, DateReceived,
        case when lag(VendorID) over(order by DateReceived) <> VendorID then 1 else 0 end as rn
    from Table1
), cte2 as (
    select
        VendorID, Quantity, sum(rn) over(order by DateReceived) as s
    from cte 
)
select
    VendorID, sum(Quantity)
from cte2
group by VendorID, s
order by s asc

尝试以下解决方案：

SELECT  z.VendorID, z.GroupID,
        MIN(z.DateReceived) AS DateReceivedStart, 
        MAX(z.DateReceived) AS DateReceivedStop, 
        SUM(z.Quantity) AS SumOfQuantity
FROM
(
    SELECT  y.VendorID,
            y.RowNum1 - y.RowNum2 AS GroupID,
            y.DateReceived,
            y.Quantity
    FROM 
    (
        SELECT  *, ROW_NUMBER() OVER(ORDER BY x.DateReceived) AS RowNum1,
                   ROW_NUMBER() OVER(ORDER BY x.VendorID, x.DateReceived) AS RowNum2
        FROM    @MyTable x
    ) y
) z
GROUP BY z.VendorID, z.GroupID
ORDER BY DateReceivedStart

您使用的是什么版本的SQL Server？您所说的“相邻”是什么意思？正如在
VendorID中一样
是另一个的+/-1吗？@w0lf我使用的是SQL server2005@Romoku实际上，真实数据中的
VendorID
是一个GUID。我所说的“相邻”是指按接收日期排序时彼此相邻。我还问了MySQL同样的问题：SQL Server 2005及以上版本
SELECT  z.VendorID, z.GroupID,
        MIN(z.DateReceived) AS DateReceivedStart, 
        MAX(z.DateReceived) AS DateReceivedStop, 
        SUM(z.Quantity) AS SumOfQuantity
FROM
(
    SELECT  y.VendorID,
            y.RowNum1 - y.RowNum2 AS GroupID,
            y.DateReceived,
            y.Quantity
    FROM 
    (
        SELECT  *, ROW_NUMBER() OVER(ORDER BY x.DateReceived) AS RowNum1,
                   ROW_NUMBER() OVER(ORDER BY x.VendorID, x.DateReceived) AS RowNum2
        FROM    @MyTable x
    ) y
) z
GROUP BY z.VendorID, z.GroupID
ORDER BY DateReceivedStart