Sql 从表中检索信息
我需要检索工资高于其部门平均工资的员工的信息。。。我们有10个、20个、30个、40个、50个。。。如此下去。在这里,我只为一个部门找到了我需要的东西。(40)我怎样才能为尽可能多的部门做到这一点 这是我的疑问:Sql 从表中检索信息,sql,Sql,我需要检索工资高于其部门平均工资的员工的信息。。。我们有10个、20个、30个、40个、50个。。。如此下去。在这里,我只为一个部门找到了我需要的东西。(40)我怎样才能为尽可能多的部门做到这一点 这是我的疑问: SELECT * FROM EMPLOYEE where (Department_ID='40')and ( employee_salary > (select avg(employee_salary) from EMPLOYEE where Depart
SELECT * FROM EMPLOYEE where (Department_ID='40')and
(
employee_salary >
(select avg(employee_salary) from EMPLOYEE where Department_ID='40')
)
数据表
:
尝试此查询
select * from EMPLOYEE as e1
where e1.employee_salary > (select avg(employee_salary)
from EMPLOYEE as e2
where e1.department_id=e2.department_id
group by Department_id)
请尝试此查询
select * from EMPLOYEE as e1
where e1.employee_salary > (select avg(employee_salary)
from EMPLOYEE as e2
where e1.department_id=e2.department_id
group by Department_id)
希望这样就行了,
SELECT emp.* FROM EMPLOYEE emp where emp.employee_salary >
( select avg(employee_salary) from EMPLOYEE new1
where emp.Department_ID=new1.Department_ID
group by Department_ID
)
希望这样就行了,
SELECT emp.* FROM EMPLOYEE emp where emp.employee_salary >
( select avg(employee_salary) from EMPLOYEE new1
where emp.Department_ID=new1.Department_ID
group by Department_ID
)
您可以尝试以下方法:
SELECT *, avg(employee_salary) as average_salary
FROM EMPLOYEE
where Department_ID='40'
having average_salary<employee_salary
选择*,平均(员工工资)作为平均工资
来自员工
哪个部门?'u ID='40'
拥有平均工资您可以尝试以下方法:
SELECT *, avg(employee_salary) as average_salary
FROM EMPLOYEE
where Department_ID='40'
having average_salary<employee_salary
选择*,平均(员工工资)作为平均工资
来自员工
哪个部门?'u ID='40'
让平均工资先提供您的表格结构。先提供您的表格结构。非常感谢您的帮助!那么您创建了两个表来进行比较?我说的对吗?@user1915345他没有创建两个表。他使用的是同一张表,有不同的别名。所以这张桌子实际上只是在和自己比较。非常感谢你的帮助!那么您创建了两个表来进行比较?我说的对吗?@user1915345他没有创建两个表。他使用的是同一张表,有不同的别名。所以这个表实际上只是和它自己比较。