SQL Server中具有唯一列的聚合结果

我在表上执行聚合，下面是我正在查询的作业表的快照

我的问题与下面类似。实际上，上述派生表将有更多列作为多个联接的结果

select Attribute   
from Job 
where Description = 'Installation' and Attribute = 'NPL' 
group by Attribute 
having sum(Cost) >= 500

我想获得匹配记录的

JobID

，因为它是唯一的，我可以使用它进行进一步的连接。如何获取匹配记录的jobID（即PK）

我不确定这样做是否合适

select Attribute, JobID 
from Job 
where Description = 'Installation' and Attribute = 'NPL' 
group by Attribute, JobID  
having sum(Cost) >= 500

我期望结果如下（对于上述场景）

---

以这种方式分组不会得到预期的结果：

Group by Attribute, JobID

这样，

JobID=34

和

JobID=39

将在单独的组中。有几种可能的方法之一是使用

内部联接

和子查询来实现“预期结果”图片：

select j.Attribute, j.JobID   
from Job j
    inner join
        (select Attribute   
         from Job 
         where Description = 'Installation' and j.Attribute = 'NPL' 
         group by Attribute 
         having sum(Cost) >= 500) a on a.Attribute = j.Attribute
where j.Description = 'Installation' and j.Attribute = 'NPL'

---

以这种方式分组不会得到预期的结果：

Group by Attribute, JobID

这样，

JobID=34

和

JobID=39

将在单独的组中。有几种可能的方法之一是使用

内部联接

和子查询来实现“预期结果”图片：

select j.Attribute, j.JobID   
from Job j
    inner join
        (select Attribute   
         from Job 
         where Description = 'Installation' and j.Attribute = 'NPL' 
         group by Attribute 
         having sum(Cost) >= 500) a on a.Attribute = j.Attribute
where j.Description = 'Installation' and j.Attribute = 'NPL'

---

可以将聚合与窗口函数一起使用，以便保留原始行，但可以对聚合值进行推理。您需要在子查询或CTE中计算聚合：

;With Totals as (
    select *,SUM(Cost) OVER (PARTITION BY Attribute) as TotalCost
    from Job
    where Description = 'Installation' and Attribute = 'NPL' 
)
select * from Totals where TotalCost > 500

---

可以将聚合与窗口函数一起使用，以便保留原始行，但可以对聚合值进行推理。您需要在子查询或CTE中计算聚合：

;With Totals as (
    select *,SUM(Cost) OVER (PARTITION BY Attribute) as TotalCost
    from Job
    where Description = 'Installation' and Attribute = 'NPL' 
)
select * from Totals where TotalCost > 500

试试这个

    SELECT 
        J.JobId,
        J.Description 
    FROM dbo.Jobs J
    INNER JOIN
    (
        SELECT 
            Attribute
        FROM dbo.Jobs
        GROUP BY
            Attribute
        having 
            sum(Cost) >= 500
    ) AS G
    ON J.Attribute = G.Attribute 
    where 
        J.Description = 'Installation' 
        and J.Attribute = 'NPL' 

试试这个

    SELECT 
        J.JobId,
        J.Description 
    FROM dbo.Jobs J
    INNER JOIN
    (
        SELECT 
            Attribute
        FROM dbo.Jobs
        GROUP BY
            Attribute
        having 
            sum(Cost) >= 500
    ) AS G
    ON J.Attribute = G.Attribute 
    where 
        J.Description = 'Installation' 
        and J.Attribute = 'NPL' 

---

你能告诉我你的输出应该是什么样子吗？嗨，Vijaykumar，我刚刚编辑了这个问题以添加我要查找的结果表。你能告诉我你的输出应该是什么样子吗？嗨，Vijaykumar，我刚刚编辑了这个问题以添加我正在寻找的结果表。但是属性不是唯一的，所以它可能会在其他场景中与不需要的记录匹配，不是吗？但是属性不是唯一的，所以它可能会在其他场景中与不需要的记录匹配，不是吗？？