Sql 获取最小值（id）和相应的其他字段以及原始字段

我有一个表e ms sql，它有下面的结构和数据-

+----+-------+-------+-------+-------+
| Id |  colx |  coly |  colz |  cola |
+----+-------+-------+-------+-------+
|  1 | x1    | y1    | z1    | a     |
|  2 | x2    | y2    | y2    | a     |
|  3 | x3    | y3    | z3    | a     |
|  4 | x4    | y4    | y4    | a     |
|  5 | x5    | y5    | z5    | b     |
|  6 | x6    | y6    | z6    | b     |
+----+-------+-------+-------+-------+

我想要cola=a的select查询结果，其中colx和id应该来自cola=a和coly=colz的组的minid。。。。结果-

+------+---------+---------+---------+---------+
| RsId |  rscolx |  rscoly |  rscolz |  rscola |
+------+---------+---------+---------+---------+
|    2 | x2      | y1      | z1      | a       |
|    2 | x2      | y2      | y2      | a       |
|    2 | x2      | y3      | z3      | a       |
|    2 | x2      | y4      | y4      | a       |
+------+---------+---------+---------+---------+

---

您可以使用窗口函数。以下使用两个步骤：

这是我的sql还是MSSQL？

select t.*,
       min(case when id = min_id then colx end) over (partition by cola)
from (select t.*,
             min(case when coly = colz then id end) over (partition by cola) as min_id
      from t
      where cola = 'a'
     ) t;