Sql 带分组的MS访问等级GPA

Sql 带分组的MS访问等级GPA,sql,ms-access,group-by,rank,Sql,Ms Access,Group By,Rank,我已经接近找到一个分组排名的答案,但还不完全。我有两张桌子 组织表 Chapter Council DDD IFC DT IFC GG IFC AA MGC BB MGC CC MGC DD IND EE IND 排班 Chapter GRDPoints TakeGPA MemberName Status DDD 2.0 2 Bill Active DT

我已经接近找到一个分组排名的答案,但还不完全。我有两张桌子

组织表

Chapter Council
DDD     IFC
DT      IFC
GG      IFC
AA      MGC
BB      MGC
CC      MGC
DD      IND
EE      IND
排班

Chapter GRDPoints  TakeGPA  MemberName  Status
DDD    2.0           2         Bill     Active
DT     3.2           3         Jim      New Member
GG     4.0           6         Sue      New Member
AA     2.3           6         Jill     Active
BB     1.3           5         Joe      New Member
CC     3.2           5         Frank    Active
DD     3.2           4         Leslie   Active
EE     4.0           3         Sandra   Active
我必须计算每一章的平均成绩,然后根据委员会对它们进行排名和分组。我没有问题计算GPA,然后再进行子查询以获得其他值,但我似乎无法让排名起作用。下面是我的SQL。我错过了什么让理事会对GPA进行排名

SELECT 
    Org.Council, 
    Org.Chapter, 
    Round((Sum(PSRoster.GrdPoints)/Sum(PSRoster.TakeGPA)),3) AS [Chapter Average],
    ( 
        Select Round((Sum(PSRoster.GrdPoints)/Sum(PSRoster.TakeGPA)),3) AS [Chapter Average] 
        FROM Org INNER JOIN PSRoster ON Org.Chapter = PSRoster.Chapter 
        WHERE PSRoster.Status = 'Active'  
    ) AS [Active Avg GPA],
    ( 
        Select Round((Sum(PSRoster.GrdPoints)/Sum(PSRoster.TakeGPA)),3) AS [Chapter Average] 
        FROM Org 
        INNER JOIN PSRoster ON Org.Chapter = PSRoster.Chapter 
        WHERE PSRoster.Status = 'New Member'  
    ) AS [New Member Avg GPA],
    (
        SELECT COUNT(PSRoster.Semester) AS [Total Number of 4] 
        FROM PSRoster 
        WHERE (PSRoster.Semester = 4.00  ) And Org.Chapter = PSRoster.Chapter 
    ) AS [FourOs]
FROM Org INNER JOIN PSRoster ON Org.Chapter = PSRoster.Chapter
Group By Org.Council, Org.Chapter;

我不能在聚合函数中进行计数。