Sql Oracle数据透视/解码
样本表Sql Oracle数据透视/解码,sql,oracle,pivot-table,Sql,Oracle,Pivot Table,样本表 EmployeeID | AssignmentID | WageCode | CompanyName | BillRate | BillTotal 1 | 1 | Regular | CompanyOne | 10 | 400 1 | 2 | Regular | CompanyTwo | 11 | 440 1 | 1
EmployeeID | AssignmentID | WageCode | CompanyName | BillRate | BillTotal
1 | 1 | Regular | CompanyOne | 10 | 400
1 | 2 | Regular | CompanyTwo | 11 | 440
1 | 1 | Overtime | CompanyOne | 15 | 150
1 | 1 | Mileage | CompanyOne | 0 | 20
2 | 3 | Regular | CompanyThree| 20 | 800
2 | 3 | Regular | CompanyThree| 20 | 800
2 | 3 | Overtime | CompanyThree| 30 | 90
2 | 3 | Mileage | CompanyThree| 0 | 60
我只想显示WageCode为“常规”的行,按EmployeeID、WageCode、AssignmentID、CompanyName和BillRate分组,并将其他工资代码透视到列中
最终结果应如下所示:
EmployeeID | AssignmentID | CompanyName | RegBillRate | RegBill | OTBillRate | OTBill | MileageBill
1 | 1 | CompanyOne | 10 | 400 | 15 | 150 | 20
1 | 2 | CompanyTwo | 11 | 440 | 0 | 0 | 0
2 | 3 | CompanyThree| 20 | 1600 | 30 | 90 | 60
with regular as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Regular' group by EmployeeID, AssignmentID, CompanyName, BillRate
),
overtime as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Overtime' group by EmployeeID, AssignmentID, CompanyName, BillRate
),
mileage as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Mileage' group by EmployeeID, AssignmentID, CompanyName, BillRate
)
select r.*, o.BillRate, o.Total, m.Total
from regular r
left outer join overtime o
on r.EmployeeID = o.EmployeeID and r.AssignmentID= o.AssignmentID and r.CompanyName= o.CompanyName and r.BillRate= o.BillRateand
left outer join mileage m
on r.EmployeeID = m.EmployeeID and r.AssignmentID= m.AssignmentID and r.CompanyName= m.CompanyName and r.BillRate= m.BillRateand
有什么更干净的方法可以做到这一点,而不是一堆这样的陈述:
EmployeeID | AssignmentID | CompanyName | RegBillRate | RegBill | OTBillRate | OTBill | MileageBill
1 | 1 | CompanyOne | 10 | 400 | 15 | 150 | 20
1 | 2 | CompanyTwo | 11 | 440 | 0 | 0 | 0
2 | 3 | CompanyThree| 20 | 1600 | 30 | 90 | 60
with regular as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Regular' group by EmployeeID, AssignmentID, CompanyName, BillRate
),
overtime as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Overtime' group by EmployeeID, AssignmentID, CompanyName, BillRate
),
mileage as
(select EmployeeID, AssignmentID, CompanyName, BillRate, sum(BillTotal) Total from SampleTable where wage code = 'Mileage' group by EmployeeID, AssignmentID, CompanyName, BillRate
)
select r.*, o.BillRate, o.Total, m.Total
from regular r
left outer join overtime o
on r.EmployeeID = o.EmployeeID and r.AssignmentID= o.AssignmentID and r.CompanyName= o.CompanyName and r.BillRate= o.BillRateand
left outer join mileage m
on r.EmployeeID = m.EmployeeID and r.AssignmentID= m.AssignmentID and r.CompanyName= m.CompanyName and r.BillRate= m.BillRateand
上面的查询是经过解释的,可能不起作用
通过解码和透视的结合,有什么更好的方法可以做到这一点?是否可以使用单个透视表?我认为您只需要条件聚合:
select EmployeeID, AssignmentID, CompanyName,
sum(case when WageCode = 'Regular' then billrate end) as regular_billrate,
sum(case when WageCode = 'Regular' then BillTotal end) as regular_billtotal,
sum(case when WageCode = 'Overtime' then billrate end) as ot_billrate,
sum(case when WageCode = 'Overtime' then BillTotal end) as ot_billtotal,
sum(case when WageCode = 'Mileage' then billrate end) as mileage_billrate,
sum(case when WageCode = 'Mileage' then BillTotal end) as mileage_billtotal
from SampleTable st
group by EmployeeID, AssignmentID, CompanyName;
我认为您只需要条件聚合:
select EmployeeID, AssignmentID, CompanyName,
sum(case when WageCode = 'Regular' then billrate end) as regular_billrate,
sum(case when WageCode = 'Regular' then BillTotal end) as regular_billtotal,
sum(case when WageCode = 'Overtime' then billrate end) as ot_billrate,
sum(case when WageCode = 'Overtime' then BillTotal end) as ot_billtotal,
sum(case when WageCode = 'Mileage' then billrate end) as mileage_billrate,
sum(case when WageCode = 'Mileage' then BillTotal end) as mileage_billtotal
from SampleTable st
group by EmployeeID, AssignmentID, CompanyName;
PIVOT:Oracle PIVOT子句允许您从Oracle 11g开始编写交叉表格查询。这意味着您可以聚合结果并将行旋转为列 解码:Oracle/PLSQL解码函数具有IF-THEN-ELSE语句的功能 对于您的用例,您可以通过以下方式使用pivot和decode:
SELECT
EmployeeID, AssignmentID, CompanyName,
decode(REG_BILLRATE, NULL, 0, REG_BILLRATE) AS REG_BILLRATE,
decode(REG_FILL, NULL, 0, REG_FILL) AS REG_FILL,
decode(OT_BILLRATE, NULL, 0, OT_BILLRATE) AS OT_BILLRATE,
decode(OT_FILL, NULL, 0, OT_FILL) AS OT_FILL,
decode(MILEAGE_FILL, NULL, 0, MILEAGE_FILL) AS MILEAGE_FILL
FROM nbitra.tmp
pivot
(
max(BillRate) AS BillRate, sum(BillTotal) AS Fill
for WageCode IN ('Regular' Reg , 'Overtime' OT , 'Mileage' Mileage )
);
注意:代码将null替换为0。PIVOT:Oracle PIVOT子句允许您从Oracle 11g开始编写交叉表格查询。这意味着您可以聚合结果并将行旋转为列 解码:Oracle/PLSQL解码函数具有IF-THEN-ELSE语句的功能 对于您的用例,您可以通过以下方式使用pivot和decode:
SELECT
EmployeeID, AssignmentID, CompanyName,
decode(REG_BILLRATE, NULL, 0, REG_BILLRATE) AS REG_BILLRATE,
decode(REG_FILL, NULL, 0, REG_FILL) AS REG_FILL,
decode(OT_BILLRATE, NULL, 0, OT_BILLRATE) AS OT_BILLRATE,
decode(OT_FILL, NULL, 0, OT_FILL) AS OT_FILL,
decode(MILEAGE_FILL, NULL, 0, MILEAGE_FILL) AS MILEAGE_FILL
FROM nbitra.tmp
pivot
(
max(BillRate) AS BillRate, sum(BillTotal) AS Fill
for WageCode IN ('Regular' Reg , 'Overtime' OT , 'Mileage' Mileage )
);
注意:代码将空值替换为0。这很接近,但最后的行太多,而大多数求和列都为空。@Alex03。是的,您会注意到我从
选择中删除了WageCode
,但没有从分组中删除。哎呀,我错了!我知道你的意思,但由于某种原因,我还是无法让它发挥作用。但这是一个有效的解决方案。总结账单价格让我有点害怕,但在我的情况下,这并不重要,因为每个组的账单价格都是唯一的。谢谢。@Alex03。您可以改用max()
。我不确定您真正想要的是哪种逻辑。这很接近,但您最终得到的行太多,而大多数求和列都为空。@Alex03。是的,您会注意到我从选择中删除了WageCode
,但没有从分组中删除。哎呀,我错了!我知道你的意思,但由于某种原因,我还是无法让它发挥作用。但这是一个有效的解决方案。总结账单价格让我有点害怕,但在我的情况下,这并不重要,因为每个组的账单价格都是唯一的。谢谢。@Alex03。您可以改用max()
。我不知道你真正想要的是什么逻辑。这是我见过的最令人惊奇的事情。你真棒!很高兴你喜欢这个解决方案!:)神奇的这是我见过的最令人惊奇的事情。你真棒!很高兴你喜欢这个解决方案!:)