比较SQL Server中同一列的两个值

我有两个表

workorder

和

woactivity

create table workorder
(
     id varchar(10), 
     description varchar(1)
);

insert into workorder (id, description)
values ('M37603', 'A'), ('M38440', 'B'), ('M38447', 'C');

create table woactivity
(
     PARENT varchar(10), 
     taskid int,
     result varchar(4)
)

insert into woactivity (PARENT, taskid, result)
values ('M37603', 1, 'PASS'), ('M37603', 2, 'FAIL'), ('M37603', 3, 'PASS'),
       ('M38440', 1, 'FAIL'), ('M38440', 2, 'FAIL'), ('M38447', 1, 'PASS'), 
       ('M38447', 2, 'PASS')

如果我在这两个表之间创建关系：

SELECT 
    WORKORDER.id, WOACTIVITY.taskid, WOACTIVITY.result   
FROM 
    WORKORDER   
LEFT JOIN 
    WOACTIVITY ON WOACTIVITY.PARENT = WORKORDER.id ;

我得到这个输出：

id    taskid result
--------------------    
M37603  1   PASS 
M37603  2   FAIL
M37603  3   PASS
M38440  1   FAIL
M38440  2   FAIL
M38447  1   PASS
M38447  2   PASS

但是我想要的是，如果每个id的任何结果都失败，那么最终结果应该显示fail，如果id的所有结果都通过，那么最终结果就是通过-如下所示：

 id      result
--------------------    
M37603  FAIL
M38440  FAIL
M38447  PASS

---

您可以通过聚合执行此操作：

select id, min(result) as result
from t
group by id

---

您可以通过聚合执行此操作：

select id, min(result) as result
from t
group by id

---

规则很简单。我们按id分组，按结果排序，显示结果，行数=1

;
WITH
cte_tmp
AS
(
    SELECT
        WORKORDER.id,
        ROW_NUMBER() OVER (PARTITION BY WORKORDER.id ORDER BY WOACTIVITY.result) AS rn,
        WOACTIVITY.result
    FROM
        workorder AS WORKORDER
        LEFT JOIN
            woactivity AS WOACTIVITY
            ON WOACTIVITY.PARENT = WORKORDER.id
)
SELECT id, result FROM cte_tmp WHERE rn = 1

---

规则很简单。我们按id分组，按结果排序，显示结果，行数=1

;
WITH
cte_tmp
AS
(
    SELECT
        WORKORDER.id,
        ROW_NUMBER() OVER (PARTITION BY WORKORDER.id ORDER BY WOACTIVITY.result) AS rn,
        WOACTIVITY.result
    FROM
        workorder AS WORKORDER
        LEFT JOIN
            woactivity AS WOACTIVITY
            ON WOACTIVITY.PARENT = WORKORDER.id
)
SELECT id, result FROM cte_tmp WHERE rn = 1

---

谢谢杀手皇后谢谢杀手皇后