如何在sql中以间隔形式显示数据 我有一张这样的桌子：

期望输出如下：-

   Marks    CLass12th  class9th  class10th
    0-25       1            1       1
    25-50      1            0       0       
    50-60      1            0       1
    60-70      0            1       1
    Total      3            2       3

如何对sql执行同样的操作

CREATE TABLE marks 
  ( 
     id    INT, 
     class VARCHAR(200), 
     marks INT 
  ); 

INSERT INTO marks 
VALUES     (1, 
            '12th', 
            0); 

INSERT INTO marks 
VALUES     (1, 
            '10th', 
            25); 

INSERT INTO marks 
VALUES     (1, 
            '9th', 
            24); 

INSERT INTO marks 
VALUES     (1, 
            '12th', 
            50); 

INSERT INTO marks 
VALUES     (1, 
            '10th', 
            60); 

INSERT INTO marks 
VALUES     (1, 
            '9th', 
            70); 

---无法在标记中设置0-24条件，因为它实际上减去值-24---

SELECT CASE 
         WHEN marks >= 0 
              AND marks < 25 THEN ( 024 ) 
         WHEN marks >= 25 
              AND marks <= 50 THEN ( 2550 ) 
         WHEN marks >= 51 
              AND marks < 60 THEN ( 5160 ) 
         WHEN marks >= 60 
              AND marks < 71 THEN ( 6070 ) 
         ELSE NULL 
       END            AS marks, 
       Sum(class12th) AS CLass12th, 
       Sum(class10th) AS CLass9th, 
       Sum(class9th)  AS CLass9th 
FROM   (SELECT id, 
               marks, 
               [12th] AS CLass12th, 
               [10th] AS CLass10th, 
               [9th]  AS CLass9th 
        FROM   (SELECT id, 
                       class, 
                       marks 
                FROM   marks) AS SourceTable 
               PIVOT ( Count(class) 
                     FOR class IN ([12th], 
                                   [10th], 
                                   [9th]) ) AS pivottable)a 
GROUP  BY marks 

试试这个：

select '0-25', sum(case when class = '12th' then 1 else 0 end) '12th',sum(case when class = '10th' then 1 else 0 end) '10th',sum(case when class = '9th' then 1 else 0 end) '9th'
from Yourtable where marks >= 0 and marks < = 25
union
select '25-50', sum(case when class = '12th' then 1 else 0 end),sum(case when class = '10th' then 1 else 0 end),sum(case when class = '9th' then 1 else 0 end)
from Yourtable where marks >= 25 and marks < = 50
union
select '50-60', sum(case when class = '12th' then 1 else 0 end),sum(case when class = '10th' then 1 else 0 end),sum(case when class = '9th' then 1 else 0 end)
from Yourtable where marks >= 50 and marks < = 60
union
select '60-70', sum(case when class = '12th' then 1 else 0 end),sum(case when class = '10th' then 1 else 0 end),sum(case when class = '9th' then 1 else 0 end)
from Yourtable where marks >= 60 and marks < = 70
union
select 'total', sum(case when class = '12th' then 1 else 0 end),sum(case when class = '10th' then 1 else 0 end),sum(case when class = '9th' then 1 else 0 end)
from Yourtable

---

您需要使用CTE存储您的范围，并在如下查询中使用它：

;with ranges as (
    select 0 fromMark, 25 toMark, '0-25' title
    union all select 25,50, '25-50'
    union all select 50,60, '50-60'
    union all select 60,70, '60-70'
    union all select 0,100, 'Total'
)
select 
    r.title,
    count(case when t.Class = '12th' then 1 end) Class12th,
    count(case when t.Class = '09th' then 1 end) Class9th,
    count(case when t.Class = '10th' then 1 end) Class10th
from yourTable t
left join ranges r
  on t.Marks >= r.fromMark and t.Marks < r.toMark
group by 
    r.title;

---

标记哪个DBMSQL服务器、MySQL、PostgreSQL等。。。您使用的是第12列，第9列是静态的，还是在出现第8列的新行时有所变化？类是静态的DBMS是SQL SERVER@ValericStill，我们需要了解如何从示例数据（原始数据或非原始数据）生成所需输出的逻辑

;with ranges as (
    select 0 fromMark, 25 toMark, '0-25' title
    union all select 25,50, '25-50'
    union all select 50,60, '50-60'
    union all select 60,70, '60-70'
    union all select 0,100, 'Total'
)
select 
    r.title,
    count(case when t.Class = '12th' then 1 end) Class12th,
    count(case when t.Class = '09th' then 1 end) Class9th,
    count(case when t.Class = '10th' then 1 end) Class10th
from yourTable t
left join ranges r
  on t.Marks >= r.fromMark and t.Marks < r.toMark
group by 
    r.title;