SQL Server从多个表中选择

我正在创建时间表应用程序，并具有以下表格

tblTimeEntry

：

-entryID (int)
-entryDate (datetime)
-enteredDate (datetime)
-entryUser (int)
-entryJob (int)
-entryTask (int)
-entryWeekNo (int)

tblWagesWeeks

：

-weekID (int)
-weekDay (int)
-date (datetime)

tblWagesWeeks

包含

weekID

，这是一个每周分配一个int的int

weekDay

是1-7之间的整数，将整数分配给一周中的每一天。已在

tblWagesWeeks

中输入了三年的日期，并带有相应的

weekDay

编号和

weekID

编号

tblTimeEntry

用于记录分配给日期的时间条目

tblTimeEntry.entryWeekNo

与

tblWagesWeeks.weekID

匹配，是一个表示周数的整数

tblTimeEntry.entryDate

匹配

tblWagesWeeks.date

并且是

datetime

因此，对于前端，我将显示一个显示周数的列表视图。用户单击一周并显示该周的天数。当用户单击某一天时，他们可以输入时间条目

我遇到的问题是，当我尝试使用以下查询列出一周的时间条目时

SELECT 
    *,   
    CONVERT(varchar(19),CONVERT(date,date,106),103) AS dateFormatted,
    CASE 
       WHEN entryHalfDay = '1' 
          THEN 'Half Day' 
       WHEN entryHalfDay = '0' 
          THEN '' 
    END AS [entryHalfDayString], 
    CASE 
       WHEN entryFullDay = '1' 
         THEN 'Full Day' 
       WHEN entryFullDay = '0' 
         THEN '' 
    END AS [entryFullDayString], 
    CASE 
       WHEN enteredDate IS NULL 
          THEN '' 
          ELSE 'Entry Complete' 
    END AS dayStatus 
FROM 
    tblWagesWeeks AS a 
LEFT JOIN 
    tblTimeEntry AS b ON a.[date] = b.entryDate 
WHERE 
    (entryUser = '1' OR entryUser IS NULL) AND weekID = '25'

我的问题是，如果我正在搜索的用户（上面查询中的“1”）在某个特定日期没有时间条目，但另一个用户有，则空日期不会显示在列表中，因此用户没有机会输入该日期的时间

下面是上面查询的输出，以演示

weekID  weekDay date    entryID entryDate   enteredDate entryUser   entryJob    entryTask   entryFullDay    entryHalfDay    entryWeekNo dateFormatted   entryHalfDayString  entryFullDayString  dayStatus
25  1   2015-06-15  23  2015-06-15  2015-07-14  1   5   5   1   0   25  15/06/2015      Full Day    Entry Complete
25  2   2015-06-16  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    16/06/2015  NULL    NULL    
25  3   2015-06-17  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    17/06/2015  NULL    NULL    
25  4   2015-06-18  26  2015-06-18  2015-07-14  1   2   2   1   0   25  18/06/2015      Full Day    Entry Complete
25  5   2015-06-19  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    19/06/2015  NULL    NULL    
25  7   2015-06-21  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    21/06/2015  NULL    NULL    

正如你所看到的，第六天不见了

当我使用entryUser=25搜索同一周时，您可以看到第6天有一个条目

SELECT *, CONVERT(varchar(19),CONVERT(date,date,106),103) AS dateFormatted,
CASE WHEN entryHalfDay='1' THEN 'Half Day' WHEN entryHalfDay='0' THEN '' END AS [entryHalfDayString], 
CASE WHEN entryFullDay='1' THEN 'Full Day' WHEN entryFullDay='0' THEN '' END AS [entryFullDayString], 
CASE WHEN enteredDate IS NULL THEN '' ELSE 'Entry Complete' END AS dayStatus 
FROM tblWagesWeeks AS a LEFT JOIN tblTimeEntry AS b ON a.[date] = b.entryDate 
WHERE (entryUser = '25' OR entryUser IS NULL) AND weekID = '25'

weekID  weekDay date    entryID entryDate   enteredDate entryUser   entryJob    entryTask   entryFullDay    entryHalfDay    entryWeekNo dateFormatted   entryHalfDayString  entryFullDayString  dayStatus
25  1   2015-06-15  23  2015-06-15  2015-07-14  1   5   5   1   0   25  15/06/2015      Full Day    Entry Complete
25  2   2015-06-16  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    16/06/2015  NULL    NULL    
25  3   2015-06-17  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    17/06/2015  NULL    NULL    
25  4   2015-06-18  26  2015-06-18  2015-07-14  1   2   2   1   0   25  18/06/2015      Full Day    Entry Complete
25  5   2015-06-19  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    19/06/2015  NULL    NULL    
25  7   2015-06-21  NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    NULL    21/06/2015  NULL    NULL    

因此，我需要知道如何始终在列表中显示所有周日，为单个用户和单个周数显示为空白并填充

---

非常感谢您的帮助。

您需要将join和week的用户条件作为主表的条件，如下所示：

SELECT *, CONVERT(varchar(19),CONVERT(date,date,106),103) AS dateFormatted,
CASE WHEN entryHalfDay='1' THEN 'Half Day' WHEN entryHalfDay='0' THEN '' END AS [entryHalfDayString], 
CASE WHEN entryFullDay='1' THEN 'Full Day' WHEN entryFullDay='0' THEN '' END AS [entryFullDayString], 
CASE WHEN enteredDate IS NULL THEN '' ELSE 'Entry Complete' END AS dayStatus 
FROM tblWagesWeeks AS a 
LEFT JOIN tblTimeEntry AS b ON a.[date] = b.entryDate AND b.entryUser = 25
WHERE a.weekID = '25'

---

您需要将join的用户条件和week设置为主表的条件，如下所示：

SELECT *, CONVERT(varchar(19),CONVERT(date,date,106),103) AS dateFormatted,
CASE WHEN entryHalfDay='1' THEN 'Half Day' WHEN entryHalfDay='0' THEN '' END AS [entryHalfDayString], 
CASE WHEN entryFullDay='1' THEN 'Full Day' WHEN entryFullDay='0' THEN '' END AS [entryFullDayString], 
CASE WHEN enteredDate IS NULL THEN '' ELSE 'Entry Complete' END AS dayStatus 
FROM tblWagesWeeks AS a 
LEFT JOIN tblTimeEntry AS b ON a.[date] = b.entryDate AND b.entryUser = 25
WHERE a.weekID = '25'

---

这两张表看起来完全一样这两张表看起来完全一样