Sql 基于日期间隔的数据透视表求和

我真的想问一下sql server中的pivot表。我试图做一些查询，结构是这样的

DECLARE @cols AS NVARCHAR(MAX) 
DECLARE @query  AS NVARCHAR(MAX)
DECLARE @tanggal_awal date
DECLARE @tanggal_akhir date
DECLARE @print nvarchar(MAX)

CREATE TABLE #datatable  
(
    product_id int,
    product_date date,
    product_ammount int
)

SET @tanggal_awal = convert(date,'02-01-2017')
SET @tanggal_akhir = convert(date,'02-27-2017')



insert into #datatable (product_id,product_date,product_ammount) VALUES 
            (1,getdate(),100),
            (1,getdate(),900),
            (2,dateadd(DD,-1,getdate()),400),
            (3,DATEADD(DD,4,getdate()),300),
            (1,dateadd(DD,4,getdate()),200),
            (2,dateadd(DD,2,getdate()),700),
            (4,dateadd(DD,-3,getdate()),1000)

--SELECT * FROM @datatable

;WITH CTE (datelist,maxdate) AS 
(
    select min(@tanggal_awal) datelist, max(product_date) maxdate
    from #datatable
    union all
    select dateadd(dd, 1, datelist), @tanggal_akhir
    from cte
    where datelist < maxdate
) SELECT c.datelist 
    into #temp
    from cte c

select @cols =  STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120)) 
                from #temp
                FOR XML PATH(''), TYPE
                ).value('.', 'NVARCHAR(MAX)') 
                ,1,1,'')

--SELECT d.datelist, b.product_id, SUM(b.product_ammount) 
--  FROM #temp d left join #datatable b on 
--  d.datelist between @tanggal_awal and @tanggal_akhir
--  AND d.datelist = b.product_date
--  GROUP BY b.product_id, d.datelist

--select b.product_id, d.datelist, 
--                sum(b.product_ammount) PivotDate
--                from #datatable b
--                left join #temp d
--                on d.datelist between @tanggal_awal and @tanggal_akhir
--              and d.datelist = b.product_date
--group by b.product_id, d.datelist
--order by b.product_id


SET @query = 'SELECT product_id, '+@cols+' FROM 
             (
                select b.product_id, d.datelist, convert(CHAR(10), datelist, 120) PivotDate
                from #datatable b
                left join #temp d
                on d.datelist between @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date

            ) x
            pivot 
            (
                count(datelist)
                for PivotDate in (' +@cols+ ')
            ) p'

             
EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

-------------------------------------
|product_id| 2017-01-02 | 2017-02-02|
-------------------------------------
|1         | 0          | 1000      |
-------------------------------------
|2         | 900        | 0         |
-------------------------------------
|3         | 700        | 0         |
-------------------------------------

有谁能给我最好的方法来处理连接和枢轴一起，特别是在这种情况下？多谢各位

-更新 在Shaker Mirza的查询之后，结果如下所示

DECLARE @cols AS NVARCHAR(MAX) 
DECLARE @query  AS NVARCHAR(MAX)
DECLARE @tanggal_awal date
DECLARE @tanggal_akhir date
DECLARE @print nvarchar(MAX)

CREATE TABLE #datatable  
(
    product_id int,
    product_date date,
    product_ammount int
)

SET @tanggal_awal = convert(date,'02-01-2017')
SET @tanggal_akhir = convert(date,'02-27-2017')



insert into #datatable (product_id,product_date,product_ammount) VALUES 
            (1,getdate(),100),
            (1,getdate(),900),
            (2,dateadd(DD,-1,getdate()),400),
            (3,DATEADD(DD,4,getdate()),300),
            (1,dateadd(DD,4,getdate()),200),
            (2,dateadd(DD,2,getdate()),700),
            (4,dateadd(DD,-3,getdate()),1000)

--SELECT * FROM @datatable

;WITH CTE (datelist,maxdate) AS 
(
    select min(@tanggal_awal) datelist, max(product_date) maxdate
    from #datatable
    union all
    select dateadd(dd, 1, datelist), @tanggal_akhir
    from cte
    where datelist < maxdate
) SELECT c.datelist 
    into #temp
    from cte c

select @cols =  STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120)) 
                from #temp
                FOR XML PATH(''), TYPE
                ).value('.', 'NVARCHAR(MAX)') 
                ,1,1,'')

--SELECT d.datelist, b.product_id, SUM(b.product_ammount) 
--  FROM #temp d left join #datatable b on 
--  d.datelist between @tanggal_awal and @tanggal_akhir
--  AND d.datelist = b.product_date
--  GROUP BY b.product_id, d.datelist

--select b.product_id, d.datelist, 
--                sum(b.product_ammount) PivotDate
--                from #datatable b
--                left join #temp d
--                on d.datelist between @tanggal_awal and @tanggal_akhir
--              and d.datelist = b.product_date
--group by b.product_id, d.datelist
--order by b.product_id


SET @query = 'SELECT product_id, '+@cols+' FROM 
             (
                select b.product_id, d.datelist, convert(CHAR(10), datelist, 120) PivotDate
                from #datatable b
                left join #temp d
                on d.datelist between @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date

            ) x
            pivot 
            (
                count(datelist)
                for PivotDate in (' +@cols+ ')
            ) p'

             
EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

-------------------------------------
|product_id| 2017-01-02 | 2017-02-02|
-------------------------------------
|1         | 0          | 1000      |
-------------------------------------
|2         | 900        | 0         |
-------------------------------------
|3         | 700        | 0         |
-------------------------------------

---

我们可以分组吗？

试试下面的方法。我认为您需要将轴心点更改为product\u amount和qry X的总和，以使product\u amount处于选中状态

SET @query = 'SELECT product_id, '+@cols+' FROM 
             (

                select b.product_id,  convert(CHAR(10), datelist, 120) PivotDate,  product_ammount  
                from #datatable b
                left join #temp d
                on d.datelist between  @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date


            ) x
            pivot 
            (
                sum(product_ammount)
                for PivotDate in (' +@cols+ ')
            ) p'


EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

更新： 替换空值

DECLARE @COLS_ISNULL VARCHAR(MAX)='';

SELECT @COLS_ISNULL = @COLS_ISNULL +COLS_ISNULL+',' FROM (
SELECT distinct   'ISNULL('+QUOTENAME(convert(CHAR(10), datelist, 120))+',0) 'as COLS_ISNULL
                from #temp)A
--to remove last comma.
SELECT @COLS_ISNULL = SUBSTRING (@COLS_ISNULL,1,LEN(@COLS_ISNULL)-1)

并在@query的Select中替换上面的@COLS_ISNULL

SET @query = 'SELECT product_id, '+@COLS_ISNULL+' FROM 
             (

                select b.product_id,  convert(CHAR(10), datelist, 120) PivotDate,  product_ammount  
                from #datatable b
                left join #temp d
                on d.datelist between  @tanggal_awal and @tanggal_akhir
                and d.datelist = b.product_date


            ) x
            pivot 
            (
                sum(product_ammount)
                for PivotDate in (' +@cols+ ')
            ) p'

从评论中：

这是我的SSMS的输出

---

您的查询可以简化为：

SET @query = 
    'SELECT product_id, '+@cols+' FROM 
     (
         select b.product_id, b.product_ammount, 
                convert(CHAR(10), product_date, 120) PivotDate
         from #datatable b
         where product_date between @tanggal_awal and @tanggal_akhir                   
     ) x
     pivot 
     (
         sum(product_ammount)
         for PivotDate in (' +@cols+ ')
     ) p'

---

您不必将JOIN留在temp，因为pivot操作中的for子句实际上返回所有日期的列表。

基于Shaker Mirza和Giorgos Betos对这个问题的回答，我终于解决了这个问题。这是此问题的完整查询

DECLARE @cols AS NVARCHAR(MAX)
DECLARE @colswithNoNulls AS NVARCHAR(MAX)
DECLARE @query  AS NVARCHAR(MAX)
DECLARE @tanggal_awal date
DECLARE @tanggal_akhir date
DECLARE @print nvarchar(MAX)

CREATE TABLE #datatable  
(
    product_id int,
    product_date date,
    product_ammount int
)

SET @tanggal_awal = convert(date,'02-01-2017')
SET @tanggal_akhir = convert(date,'02-27-2017')



insert into #datatable (product_id,product_date,product_ammount) VALUES 
            (1,getdate(),100),
            (1,getdate(),900),
            (2,dateadd(DD,-1,getdate()),400),
            (3,DATEADD(DD,4,getdate()),300),
            (1,dateadd(DD,4,getdate()),200),
            (2,dateadd(DD,2,getdate()),700),
            (4,dateadd(DD,-3,getdate()),1000)


;WITH CTE (datelist,maxdate) AS 
(
    select min(@tanggal_awal) datelist, max(product_date) maxdate
    from #datatable
    union all
    select dateadd(dd, 1, datelist), @tanggal_akhir
    from cte
    where datelist < maxdate
) SELECT c.datelist 
    into #temp
    from cte c

select @cols =  STUFF((SELECT distinct ',' + QUOTENAME(convert(CHAR(10), datelist, 120)) 
                from #temp
                FOR XML PATH(''), TYPE
                ).value('.', 'NVARCHAR(MAX)') 
                ,1,1,'')

select @colswithNoNulls =   STUFF((SELECT distinct ',ISNULL(' + QUOTENAME(convert(CHAR(10), datelist, 120)) +',''0'') '+ QUOTENAME(convert(CHAR(10), datelist, 120)) 
                            from #temp
                            FOR XML PATH(''), TYPE
                            ).value('.', 'NVARCHAR(MAX)') 
                            ,1,1,'')

SET @query = 
            'SELECT product_id, '+ @colswithNoNulls+' FROM 
             (
                select b.product_id, coalesce(b.product_ammount,0) as product_ammount, 
                       convert(CHAR(10), product_date, 120) PivotDate
                from #datatable b
                where product_date between @tanggal_awal and @tanggal_akhir                                
            ) x
            pivot 
            (
                sum(product_ammount)
                for PivotDate in (' +@cols+ ')
            ) p'            


EXECUTE sp_executesql @query ,N'@tanggal_awal DATE, @tanggal_akhir DATE', @tanggal_awal,@tanggal_akhir
GO
drop table #temp
go
drop table #datatable

---

这个想法来自于。这个想法本身就是制作两个不同的col，一个只用于col，另一个带有ISNULL。希望这个问题能在不久的将来解决很多问题：

它正在工作：，非常感谢。但是结果不是很好。@mirza，由于结果没有分组，如何对它进行分组？我不明白。你说的群居是什么意思@FarisFajari已经编辑了您的查询结果，希望您能帮助我：您的工作也在工作：，谢谢您的帮助和参考@Shaker Mirza。我想您的答案是最完美的。谢谢：，顺便说一句，我应该在哪里放置像coalescex，0这样的东西来删除空值？最后您得到了它