SQL:如何从递归查询创建视图?
问题:我想从递归查询中派生一个视图 查询的结构与此处的相同: 并将树视图表示为有序数据集 如何创建执行以下操作的视图:SQL:如何从递归查询创建视图?,sql,sql-server,sql-server-2008,recursion,view,Sql,Sql Server,Sql Server 2008,Recursion,View,问题:我想从递归查询中派生一个视图 查询的结构与此处的相同: 并将树视图表示为有序数据集 如何创建执行以下操作的视图: ;WITH Tree (ID, [NAME], PARENT_ID, Depth, Sort) AS ( SELECT ID, [NAME], PARENT_ID, 0 AS Depth, CONVERT(varchar(255), [Name]) AS Sort FROM Category WHERE PARENT_ID = 0 UNION ALL
;WITH Tree (ID, [NAME], PARENT_ID, Depth, Sort) AS
(
SELECT ID, [NAME], PARENT_ID, 0 AS Depth, CONVERT(varchar(255), [Name]) AS Sort FROM Category
WHERE PARENT_ID = 0
UNION ALL
SELECT CT.ID, CT.[NAME], CT.PARENT_ID, Parent.Depth + 1 AS Depth,
CONVERT(varchar(255), Parent.Sort + ' | ' + CT.[NAME]) AS Sort
FROM Category CT
INNER JOIN Tree as Parent ON Parent.ID = CT.PARENT_ID
)
-- HERE IS YOUR TREE, Depths gives you the level starting with 0 and Sort is the Name based path
SELECT ID, [NAME], PARENT_ID, Depth, Sort FROM Tree
ORDER BY Sort
它应该简单到:
CREATE VIEW YourViewName
AS
WITH Tree (ID, [NAME], PARENT_ID, Depth, Sort) AS
(
SELECT ID, [NAME], PARENT_ID, 0 AS Depth, CONVERT(varchar(255), [Name]) AS Sort
FROM Category
WHERE PARENT_ID = 0
UNION ALL
SELECT CT.ID, CT.[NAME], CT.PARENT_ID, Parent.Depth + 1 AS Depth,
CONVERT(varchar(255), Parent.Sort + ' | ' + CT.[NAME]) AS Sort
FROM Category CT
INNER JOIN Tree as Parent ON Parent.ID = CT.PARENT_ID
)
-- HERE IS YOUR TREE, Depths gives you the level starting with 0 and Sort is the Name based path
SELECT ID, [NAME], PARENT_ID, Depth, Sort FROM Tree
GO
啊,分号,对不起,我没看到。PS:不,不是那么简单,只是几乎:您需要删除ORDERBY或将top 100%添加到select语句;-)您需要删除该订单,因为它不属于视图,SQL将拒绝它anyway@Quandary,@Damien:谢谢你在订购人上的介绍。剪切粘贴编码的危害之一!:-)我将进行适当的更新。您最好创建一个内联表值函数来实现这一点。然后,您可以参数化传递给它的父Id。最好在视图中执行此操作,并可能将主根uid添加为列,然后从存储过程中查询该视图。当您有很多数据时,表值函数将变得很慢,因为它们在内存中创建临时表,如果内存不足,这些临时表将被交换。