Sql 两列之间存在不常见的ID

我有两个表，如果表2中没有任何一个ID，我需要获取。我尝试了这个查询，但没有给出正确的结果。请建议

表1

表2

输出应为：，因为这两列中都没有发布ID和购买ID

已尝试查询：

SELECT T1_ID 
FROM T1 LEFT OUTER JOIN T2
ON t1.RELEASEID=t2.RELEASEID
LEFT OUTER JOIN T2 t3
ON t1.PURCHASEID=t3.PURCHASEID
WHERE IFNULL(T2.RELEASEID,'') ='' OR IFNULL(T3.PURCHASEID,'')=''

---

您可以使用

不存在

，如下所示：

select * from t1
where not exists (select 1 from t2
where t1.releaseid =t2.releaseid or t1.purchaseid =t2.purchaseid)

select t1.*
  from t1 left join t2
    on t1.releaseid =t2.releaseid or t1.purchaseid =t2.purchaseid
 where t2.t2_id is null

您还可以使用

左连接

，如下所示：

select * from t1
where not exists (select 1 from t2
where t1.releaseid =t2.releaseid or t1.purchaseid =t2.purchaseid)

select t1.*
  from t1 left join t2
    on t1.releaseid =t2.releaseid or t1.purchaseid =t2.purchaseid
 where t2.t2_id is null

---

一种方法是

不存在

：

select t1.*
from t1
where not exists (select 1
                  from t2
                  where t2.releaseid = t1.releaseid
                 ) and
      not exists (select 1
                  from t2
                  where t2.purchaseid = t1.purchaseid
                 );

无论

？

是真正的字符串还是应该表示

NULL

，这都应该有效

注意：这可以利用

t2（releaseid）

和

t2（purchaseid）

上的索引，这可以大大提高较大数据的性能。

我想您需要：

select t1.*
from table1 t1
where 
    (t1.release_id = '?' and t2.purchase_id = '?')
    or not exists (
        select 1
        from table2 t2
        where t1.release_id in ('?', t2.release_id)
          and t1.purchase_id in ('?', t2.purchase_id)
)

---

如果问号应该表示

null

值，您可以将

='？'

的所有实例替换为

is null

，请尝试此操作，并告诉我它是否有效

SELECT * FROM TABLE1 WHERE NOT EXISTS (SELECT '1' FROM TABLE2 WHERE TABLE1 .RELEASEID=TABLE2.RELEASEID OR  TABLE1 .PURCHASEID=TABLE2.PURCHASEID);