增强SQL体系结构

我需要设计一个没有重复组的表，我想我已经这样做了，但是表的链接方式是否正确，或者有什么可以改进的吗？我运行了所有的查询，我有几个重复的球员和经理组，因为我把他们都放在了一张阵容表中，所以我把他们分成了团队球员和团队经理，这样一个或多个经理也可以管理一支球队，反之亦然，体育场等等

drop table film_director;
drop table film_actor;
drop table film;
drop table studio;
drop table actor;
drop table director;

CREATE TABLE studio(
  studio_ID NUMBER NOT NULL,
  studio_Name VARCHAR2(30),
  PRIMARY KEY(studio_ID));

CREATE TABLE film(
  film_ID NUMBER NOT NULL,
  studio_ID NUMBER NOT NULL,
  genre VARCHAR2(30),
  genre_ID NUMBER(1),
  film_Len NUMBER(3),
  film_Title VARCHAR2(30) NOT NULL,
  year_Released NUMBER NOT NULL,
  PRIMARY KEY(film_ID),
  FOREIGN KEY (studio_ID) REFERENCES studio);

CREATE TABLE director(
  director_ID NUMBER NOT NULL,
  director_fname VARCHAR2(30),
  director_lname VARCHAR2(30),
  PRIMARY KEY(director_ID));

CREATE TABLE actor(
  actor_ID NUMBER NOT NULL,
  actor_fname VARCHAR2(15),
  actor_lname VARCHAR2(15),
  PRIMARY KEY(actor_ID));

CREATE TABLE film_actor(
  film_ID NUMBER NOT NULL,
  actor_ID NUMBER NOT NULL,
  PRIMARY KEY(film_ID, actor_ID),
  FOREIGN KEY(film_ID) REFERENCES film(film_ID),
  FOREIGN KEY(actor_ID) REFERENCES actor(actor_ID));

CREATE TABLE film_director(
  film_ID NUMBER NOT NULL,
  director_ID NUMBER NOT NULL,
  PRIMARY KEY(film_ID, director_ID),
  FOREIGN KEY(film_ID) REFERENCES film(film_ID),
  FOREIGN KEY(director_ID) REFERENCES director(director_ID));

INSERT INTO studio (studio_ID, studio_Name) VALUES (1, 'Paramount');
INSERT INTO studio (studio_ID, studio_Name) VALUES (2, 'Warner Bros');
INSERT INTO studio (studio_ID, studio_Name) VALUES (3, 'Film4');
INSERT INTO studio (studio_ID, studio_Name) VALUES (4, 'Working Title Films');

INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (1, 1, 'Comedy', 1, 180, 'The Wolf Of Wall Street', 2013);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (2, 2, 'Romance', 2, 143, 'The Great Gatsby', 2013);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (3, 3, 'Science Fiction', 3, 103, 'Never Let Me Go', 2008);
INSERT INTO film (film_ID, studio_ID, genre, genre_ID, film_Len, film_Title, year_Released) VALUES (4, 4, 'Romance', 4, 127, 'Pride and Prejudice', 2005);

INSERT INTO director (director_ID, director_fname, director_lname) VALUES (1, 'Martin', 'Scorcese');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (2, 'Baz', 'Luhrmann');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (3, 'Mark', 'Romanek');
INSERT INTO director (director_ID, director_fname, director_lname) VALUES (4, 'Joe', 'Wright');

INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (1, 'Matthew', 'McConnaughy');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (2, 'Leonardo', 'DiCaprio');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (3, 'Margot', 'Robbie');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (4, 'Joanna', 'Lumley');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (5, 'Carey', 'Mulligan');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (6, 'Tobey', 'Maguire');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (7, 'Joel', 'Edgerton');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (8, 'Keira', 'Knightly');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (9, 'Andrew', 'Garfield');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (10, 'Sally', 'Hawkins');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (11, 'Judi', 'Dench');
INSERT INTO actor (actor_ID, actor_fname, actor_lname) VALUES (12, 'Matthew', 'Macfadyen');

INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 1);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 2);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 3);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (1, 4);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 2);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 6);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (2, 7);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 8);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 9);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (3, 10);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 5);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 8);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 11);
INSERT INTO film_actor (film_ID, actor_ID) VALUES (4, 12);

INSERT INTO film_director (film_ID, director_ID) VALUES (1,1);
INSERT INTO film_director (film_ID, director_ID) VALUES (2,2);
INSERT INTO film_director (film_ID, director_ID) VALUES (3,3);
INSERT INTO film_director (film_ID, director_ID) VALUES (4,4);

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我只有一张用户表（导演/演员），因为如果导演也是昆汀·塔伦蒂诺（Quentin Tarantino）这样的演员，会发生什么。您必须重复数据

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尝试将您的模型升级到BCNF或4NF，您会没事的

我同意sdmon-因为导演和演员具有相同的属性，所以将它们都放在一个表中，并在“事实”表中为它们分配角色是有意义的

一部电影可以有多个导演吗？如果不需要，则不需要film_director表，只需要film表中的“director”列。否则，您确实需要电影导演表

一部电影可以绑定到多个工作室吗？在您的模型中，在film表中有一列表示studio_id，但也有一个film_studio表。你不需要两者兼而有之。如果一部电影总是由一个工作室制作，则需要列（而不是表）。如果一部电影需要显示多个工作室，则需要额外的表，而不是列

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其他一切看起来都很好。祝你好运

不知道为什么这是用sql和oracle标记的。。。这更多的是关于数据库设计、关系数据库。。。没有任何东西与sql或OracleSystem特别相关。在系统模式中创建表不是一个好主意。只需创建一个用户并在那里完成您的工作。好习惯很早就开始了。你怎么知道只有一家制片厂会制作一部电影？是否会有多个制片厂与一部电影的合作关系？@kevinskyI是的，我刚刚在oracle中创建了一个快速模式，以帮助解决我必须在Visio中执行正确的问题。请停止用答案更改旧问题。发布一个新的。请不要复制旧帖子，只需编辑。是的，我忘记删除那个studio_id链接，因为我刚刚做了更改，但我不确定是否要删除提供给我的数据，但我想现在我会了，我可能是想得太多了。