Sql 在postgres中将结果行合并为一行

我在postrges中获得以下数据

id|    count1     count2
12     3          0
12     0          2

但我想要综合结果

我从中得到上述结果的查询

SELECT
    date_part( 'day', t1.requested_datetime ) AS requested_day,
    CASE
      WHEN date_part ( 'hour', t1.requested_datetime ) >= 0 AND date_part ( 'hour', t1.requested_datetime ) <= 11 THEN count ( date_part ( 'day', t1.requested_datetime ) )
      ELSE 0
    END AS count_am,
    CASE
      WHEN date_part ( 'hour', t1.requested_datetime ) > 11 AND date_part ( 'hour', t1.requested_datetime ) <= 23 THEN count ( date_part ( 'day', t1.requested_datetime ) )
      ELSE 0
    END AS count_pm
FROM
    table1 t1
WHERE
    date_part ( 'month', t1.requested_datetime ) = 11
    AND date_part ( 'year', t1.requested_datetime ) = 2013
GROUP BY
    requested_day,
    date_part ( 'hour', t1.requested_datetime )
ORDER BY
    date_part ( 'day', t1.requested_datetime )

请帮忙

---

谢谢

事实上，你是如何获得这些数据的，这可能会很有趣。看起来好像您已经尝试了透视数据。我已添加了从中获取结果的查询。谢谢。你救了我一天。

id    count1   count2
12    3        2

select id, 
       sum(count1) as count1,
       sum(count2) as count2
from your_table
group by id