返回材质名称的SQL

下面的代码是我创建的一个查询的结果，除了一件事之外，所有代码都可以正常工作。我有物料名称的物料ID：

1 = bath
2 = sink
3 = toilet

下面显示的是每种材质的水槽

Select cu.FName + '  ' + cu.SName as 'Name', 
cu.Address1 + ', ' + cu.Address2 + ', ' + cu.Address3 as 'Dispatch Address', 
cu.PostCode, 
co.DateOrdered,
co.Material1,
ma.MaterialName,
co.material2, 
ma.MaterialName, 
ma.Price as 'Item Price' 
from Customers cu 
left join CustomerOrder co on co.CustomerID = cu.CustomerID
left join ItemOrder it on it.OrderID = co.OrderID 
left join Materials ma on ma.MaterialID = co.Material1 
or co.material2 = ma.MaterialItemID or co.material3 = ma.MaterialItemID

它显示如下（仅列出材料以避免混淆）

---

有人能帮忙吗？

有几种方法可以做到这一点，包括多次使用

材质表上的
JOIN
，以获得结果：

Select cu.FName + '  ' + cu.SName as 'Name', 
    cu.Address1 + ', ' + cu.Address2 + ', ' + cu.Address3 as 'Dispatch Address', 
    cu.PostCode, 
    co.DateOrdered,
    co.Material1,
    ma1.MaterialName Material1Name,
    co.material2, 
    ma2.MaterialName Material2Name, 
    ma1.Price as 'Item Price',
    co.material3, 
    ma3.MaterialName  Material3Name
from Customers cu 
left join CustomerOrder co 
    on co.CustomerID = cu.CustomerID
left join ItemOrder it 
    on it.OrderID = co.OrderID 
left join Materials ma1 
    on ma1.MaterialID = co.Material1 
left join Materials ma2 
    on co.material2 = ma2.MaterialItemID
left join Materials ma3 
    on co.material3 = ma3.MaterialItemID

还有一个问题，我如何总结材质Id的值？我可以创建一行，将3个价格相加，而不是将ma1.price作为“商品价格”吗？听起来您可以使用（ma1.price+ma2.price+ma3.price）来获取商品的总价。
Select cu.FName + '  ' + cu.SName as 'Name', 
    cu.Address1 + ', ' + cu.Address2 + ', ' + cu.Address3 as 'Dispatch Address', 
    cu.PostCode, 
    co.DateOrdered,
    co.Material1,
    ma1.MaterialName Material1Name,
    co.material2, 
    ma2.MaterialName Material2Name, 
    ma1.Price as 'Item Price',
    co.material3, 
    ma3.MaterialName  Material3Name
from Customers cu 
left join CustomerOrder co 
    on co.CustomerID = cu.CustomerID
left join ItemOrder it 
    on it.OrderID = co.OrderID 
left join Materials ma1 
    on ma1.MaterialID = co.Material1 
left join Materials ma2 
    on co.material2 = ma2.MaterialItemID
left join Materials ma3 
    on co.material3 = ma3.MaterialItemID