Sql 如何根据开始日期和结束日期仅获取重叠记录？

我有一个表和查询，如下所示： 我正在尝试获取同一员工Id的[Assignment Start Date]和[Assignment End Date]之间的重叠记录。 简而言之，我需要以下示例中为相同时间段或重叠时间段分配的员工Id的数据。 e、 g

我曾尝试使用上述查询，但它会给出与重叠员工相关的所有记录，即使该员工的条目不重叠

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在上面的示例中，有一个雇员Id 102，它有两个重叠的条目，第三个条目不重叠。我想从这个结果中删除它。请提供帮助。

CTE、行号和自连接

with CTE as
(
select PK, Resource_ID, [Employee ID] as Emp_ID, [Assignment Start Date] as s_Date, [Assignment End Date] as e_date,
       row_number() over(partition by [Employee ID] order by  [Assignment Start Date] ) as rn
from #Result
)
select t1.*, t2.*
from CTE t1
inner join CTE t2
  on t1.Resource_ID = t2.Resource_ID
  and t1.Emp_ID = t2.Emp_ID
  and t2.rn = t1.rn +1
where t2.s_date <= t1.e_date 
or t1.e_date is null -- allows for null end date

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您的SQL查询应该如下所示：

SELECT DISTINCT r1.PK, r1.Resource_ID,r1.[Employee ID], r1.[Assignment Start Date] AS 'Start 1' ,r1.[Assignment End Date] AS 'End 1' , r2.[Assignment Start Date] , r2.[Assignment End Date]
INTO #temp1
FROM #Result r1
JOIN #Result r2 on r1.[Employee ID] = r2.[Employee ID]
WHERE (
(r2.[Assignment Start Date]  BETWEEN r1.[Assignment Start Date]  and r1.[Assignment End Date])
or
(r2.[Assignment End Date] between p1.[Assignment Start Date]  and p1.[Assignment End Date])
)
AND r1.PK <> r2.PK  

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如果102有一对重叠的记录呢？您期望的输出是什么？如果任何一条记录与另一条重叠，那么两条重叠的记录都应该是结果。。结果不应出现任何重叠。对于你的问题，两人都应该是结果。谁曾否决过这个问题，请给出一个理由！！！它表示无效的列名'rn'@t2.rn=t1.rn+1@NikhilPatel我的错，我没有正确引用CTE。编辑感谢您的更正。。你的回答起作用了，但有一部分。。。我得到了重叠的记录，但它没有给我一对。。。它只返回一个重叠记录。@NikhilPatel引用了第二盘CTE的第二遍，根据最新的编辑谢谢你的回答，我得到了我需要的。

SELECT DISTINCT r1.PK, r1.Resource_ID,r1.[Employee ID], r1.[Assignment Start Date] AS 'Start 1' ,r1.[Assignment End Date] AS 'End 1' , r2.[Assignment Start Date] , r2.[Assignment End Date]
INTO #temp1
FROM #Result r1
JOIN #Result r2 on r1.[Employee ID] = r2.[Employee ID]
WHERE (
(r2.[Assignment Start Date]  BETWEEN r1.[Assignment Start Date]  and r1.[Assignment End Date])
or
(r2.[Assignment End Date] between p1.[Assignment Start Date]  and p1.[Assignment End Date])
)
AND r1.PK <> r2.PK