Sql 表结构问题-查询透视/取消透视_Sql_Sql Server_Sql Server 2012

Sql 表结构问题-查询透视/取消透视

sql sql-server sql-server-2012

Sql 表结构问题-查询透视/取消透视,sql,sql-server,sql-server-2012,Sql,Sql Server,Sql Server 2012,我试图查询一个表进行数据转换，但遇到了结构问题。我猜我需要先转一转，然后再取消Pivot，但我不确定从哪里开始这是我现在的桌子 +----+-----------+-------+---------+ | ID | field | value | date | +----+-----------+-------+---------+ | 1 | Draw1 | 1500 | NULL | | 1 | Draw1Date | NULL | 4/15/16 |

我试图查询一个表进行数据转换，但遇到了结构问题。我猜我需要先转一转，然后再取消Pivot，但我不确定从哪里开始

这是我现在的桌子

+----+-----------+-------+---------+
| ID |   field   | value |  date   |
+----+-----------+-------+---------+
|  1 | Draw1     | 1500  | NULL    |
|  1 | Draw1Date | NULL  | 4/15/16 |
|  1 | Draw1Fee  | 100   | NULL    |
|  1 | Draw2     | 2000  | NULL    |
|  1 | Draw2Date | NULL  | 3/14/17 |
|  1 | Draw2Fee  | 100   | NULL    |
|  2 | Draw1     | 800   | NULL    |
|  2 | Draw1Date | NULL  | 4/16/18 |
|  2 | Draw1Fee  | 150   | NULL    |
|  2 | Draw2     | 760   | NULL    |
|  2 | Draw2Date | NULL  | 5/6/18  |
|  2 | Draw2Fee  | 150   | NULL    |
+----+-----------+-------+---------+

需要的结果

+----+-------+---------+---------+------+
| ID | Draws |  Amount |  Date   |  Fee |
+----+-------+---------+---------+------+
|  1 | Draw1 |    1500 | 4/15/16 |  100 |
|  1 | Draw2 |    2000 | 3/14/17 |  100 |
|  2 | Draw1 |     800 | 4/16/18 |  150 |
|  2 | Draw2 |     760 | 5/6/18  |  150 |
+----+-------+---------+---------+------+

我的答案适用于提供的数据。如果您正在寻找更通用的解决方案，对于更多种类的数据，您可以尝试找到另一个答案。我没有使用PIVOT/UNPIVOT

测试数据：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

查询：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

结果：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

我的答案适用于提供的数据。如果您正在寻找更通用的解决方案，对于更多种类的数据，您可以尝试找到另一个答案。我没有使用PIVOT/UNPIVOT

测试数据：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

查询：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

结果：

create table #t (ID int, field varchar(20), [value] int, [date] date)

insert into #t values 
(1 ,'Draw1'     , 1500  , NULL     ),
(1 ,'Draw1Date' , NULL  , '4/15/16'),
(1 ,'Draw1Fee'  , 100   , NULL     ),
(1 ,'Draw2'     , 2000  , NULL     ),
(1 ,'Draw2Date' , NULL  , '3/14/17'),
(1 ,'Draw2Fee'  , 100   , NULL     ),
(2 ,'Draw1'     , 800   , NULL     ),
(2 ,'Draw1Date' , NULL  , '4/16/18'),
(2 ,'Draw1Fee'  , 150   , NULL     ),
(2 ,'Draw2'     , 760   , NULL     ),
(2 ,'Draw2Date' , NULL  , '5/6/18' ),
(2 ,'Draw2Fee'  , 150   , NULL     )

;with ct as (
    select ID, field
    from #t
    where field in ('Draw1', 'Draw2')
    group by ID, field
)
select ct.ID, ct.field
, t1.[value] as Amount, t2.[date] as [Date], t3.[value] as Fee
from ct
    inner join #t t1 on t1.ID = ct.ID and t1.field = ct.field
    inner join #t t2 on t2.ID = ct.ID and t2.field = ct.field + 'Date'
    inner join #t t3 on t3.ID = ct.ID and t3.field = ct.field + 'Fee'

ID  field   Amount  Date        Fee
1   Draw1   1500    2016-04-15  100
1   Draw2   2000    2017-03-14  100
2   Draw1   800     2018-04-16  150
2   Draw2   760     2018-05-06  150

我只想：

select id, left(field, 5),
       max(case when len(field) = 5 then value end) as value,
       max(case when field like '%date' then value end) as date,
       sum(case when field like '%fee' then value end) as fee
from t
group by id, left(field, 5);

如果您的字段确实更复杂，您是否在最后查找

日期

和

费用

，然后使用

交叉应用

：

select t.id, v.draws,
       max(case when t.field = v.draws then value end) as value,
       max(case when t.field like '%date' then value end) as date,
       sum(case when t.field like '%fee' then value end) as fee
from t cross apply
     (values (replace(replace(field, 'date', ''), 'fee', '')) v(draws)
group by id, v.draws;

我只想：

select id, left(field, 5),
       max(case when len(field) = 5 then value end) as value,
       max(case when field like '%date' then value end) as date,
       sum(case when field like '%fee' then value end) as fee
from t
group by id, left(field, 5);

如果您的字段确实更复杂，您是否在最后查找

日期

和

费用

，然后使用

交叉应用

：

select t.id, v.draws,
       max(case when t.field = v.draws then value end) as value,
       max(case when t.field like '%date' then value end) as date,
       sum(case when t.field like '%fee' then value end) as fee
from t cross apply
     (values (replace(replace(field, 'date', ''), 'fee', '')) v(draws)
group by id, v.draws;

试试这个

SELECT tblAmount.id         AS ID, 
       tblAmount.field      AS Draws, 
       Max(tblAmount.value) AS Amount, 
       Max(tblDate.[date])  AS [Date], 
       Max(tblFee.value)    AS Fee 

FROM   tablename tblAmount 
       INNER JOIN (SELECT id, field, [date] 
                   FROM   tablename 
                   WHERE  [date] IS NOT NULL AND field LIKE '%Date') tblDate 
               ON tblAmount.id = tblDate.id   
                  AND tblDate.field LIKE tblAmount.field + '%'              
       INNER JOIN (SELECT id, field, value 
                   FROM   tablename 
                   WHERE  value IS NOT NULL AND field LIKE '%Fee') tblFee 
               ON tblAmount.id = tblFee.id                
WHERE  tblAmount.value IS NOT NULL 
       AND tblAmount.field NOT LIKE '%Fee' 
       AND tblAmount.field NOT LIKE '%Date' 
GROUP  BY tblAmount.id, tblAmount.field 
ORDER  BY tblAmount.id, tblAmount.field

输出

+----+-------+--------+------------+-----+
| ID | Draws | Amount |    Date    | Fee |
+----+-------+--------+------------+-----+
|  1 | Draw1 |   1500 | 2016-04-15 | 100 |
|  1 | Draw2 |   2000 | 2017-03-14 | 100 |
|  2 | Draw1 |    800 | 2018-04-16 | 150 |
|  2 | Draw2 |    760 | 2018-05-06 | 150 |
+----+-------+--------+------------+-----+

演示：

试试这个

SELECT tblAmount.id         AS ID, 
       tblAmount.field      AS Draws, 
       Max(tblAmount.value) AS Amount, 
       Max(tblDate.[date])  AS [Date], 
       Max(tblFee.value)    AS Fee 

FROM   tablename tblAmount 
       INNER JOIN (SELECT id, field, [date] 
                   FROM   tablename 
                   WHERE  [date] IS NOT NULL AND field LIKE '%Date') tblDate 
               ON tblAmount.id = tblDate.id   
                  AND tblDate.field LIKE tblAmount.field + '%'              
       INNER JOIN (SELECT id, field, value 
                   FROM   tablename 
                   WHERE  value IS NOT NULL AND field LIKE '%Fee') tblFee 
               ON tblAmount.id = tblFee.id                
WHERE  tblAmount.value IS NOT NULL 
       AND tblAmount.field NOT LIKE '%Fee' 
       AND tblAmount.field NOT LIKE '%Date' 
GROUP  BY tblAmount.id, tblAmount.field 
ORDER  BY tblAmount.id, tblAmount.field

输出

+----+-------+--------+------------+-----+
| ID | Draws | Amount |    Date    | Fee |
+----+-------+--------+------------+-----+
|  1 | Draw1 |   1500 | 2016-04-15 | 100 |
|  1 | Draw2 |   2000 | 2017-03-14 | 100 |
|  2 | Draw1 |    800 | 2018-04-16 | 150 |
|  2 | Draw2 |    760 | 2018-05-06 | 150 |
+----+-------+--------+------------+-----+

演示：

我遇到的唯一问题是SQL试图将[date]转换为smallintI，我不明白。你从哪里得到错误？所提供的查询适用于meIt，是添加到joinsYes中的+'Date'和+'Fee'。它们是连接条件的一部分实际上我得到的是整个日期列的空值我遇到的唯一问题是SQL试图将[date]转换为smallintI，我不明白。你从哪里得到错误？所提供的查询适用于meIt，是添加到joinsYes中的+'Date'和+'Fee'。它们是连接条件的一部分。实际上，我得到的是整个日期的空值column@Kharvok，对不起。小错误。“现在试试看。”哈沃克，很抱歉。小错误。现在试试看。