Sql 从两个给定时间以hh:mm格式获取时间的更好选项

输出：

9:31

我们是否有任何其他功能，我可以缩短上述脚本。另外，我应该怎么做才能将输出设置为

09:31

而不是

9:31

？

您可以在Sql Server中使用函数

更新-（示例）：这可能是您想要的：

select cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))/60 as varchar)
       +':'+cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))%60 as varchar)

RIGHT('00' + str, 2)

您可以使用样式114获得

HH:mm

select FORMAT(CONVERT(datetime,'9:31'),'HH:mm') AS 'time'

编辑

作为注释，以避免使用日期时间算法

SELECT 
    CONVERT(nvarchar(5), 
        -- Get difference of time
        CONVERT(datetime,'07:06 PM') - CONVERT(datetime,'09:35 AM')
        , 114)

声明和/或转换为

VARCHAR

类型时，应指定长度，否则SQL Server将为您指定默认值。有时是

1

，有时是

30

。有关更多信息，请参见此

此外，要将差异格式化为

hh:mm

，您需要在字符串中填入适当的零。这是通过以下方式实现的：

DECLARE @time1 AS VARCHAR(8) = '09:35 AM'
DECLARE @time2 AS VARCHAR(8) = '07:06 PM'
    
SELECT 
    time1   = CAST(@time1 AS TIME), 
    time2   = CAST(@time2 AS TIME),
    diff    = DATEDIFF(MINUTE, @time1, @time2),
    hh      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2),
    mm      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2),
    final   = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2) + ':' +
              RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2)

---

只要试试这个广告，看看这是不是你想要的：

select cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))/60 as varchar)
       +':'+cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))%60 as varchar)

RIGHT('00' + str, 2)

或

---

该版本的

格式仅在SQL Server 2012中引入。问题列在sql-server-2008下。我的查询似乎比您的短：）是的，但这并不意味着您的更好。更短并不总是等于更短。我刚刚纠正了您的
VARCHAR
转换。
SELECT (CONVERT(VARCHAR(5), GETDATE(), 114))