Sql 每周比赛的奖牌数

我有一张表，上面有球员每周的得分：

# select * from pref_money limit 5;
       id       | money |   yw
----------------+-------+---------
 OK32378280203  |   -27 | 2010-44
 OK274037315447 |   -56 | 2010-44
 OK19644992852  |     8 | 2010-44
 OK21807961329  |   114 | 2010-44
 FB1845091917   |   774 | 2010-44
(5 rows)

下面的SQL语句为我提供了每周赢家以及每位玩家赢取的次数：

# select x.id, count(x.id) from (
    select id,
           row_number() over(partition by yw order by money desc) as ranking
    from pref_money
) x
where x.ranking = 1 group by x.id;
           id           | count
------------------------+-------
 OK9521784953           |     1
 OK356310219480         |     1
 MR797911753357391363   |     1
 OK135366127143         |     1
 OK314685454941         |     1
 OK308121034308         |     1
 OK4087658302           |     5
 OK452217781481         |     6
....

我想将后一个数字保存在运动员表的奖牌栏中：

# \d pref_users;
                   Table "public.pref_users"
   Column   |            Type             |     Modifiers
------------+-----------------------------+--------------------
 id         | character varying(32)       | not null
 first_name | character varying(64)       |
 last_name  | character varying(64)       |
 city       | character varying(64)       |
 medals     | integer                     | not null default 0

请问怎么做？我只能考虑使用一张临时桌子，但必须有一个更简单的方法。。。多谢各位

更新：

Clodoaldo建议的查询有效，但现在我的cronjob偶尔会失败，原因是：

/* reset and then update medals count */
update pref_users set medals = 0;
psql:/home/afarber/bin/clean-database.sql:63: ERROR:  deadlock detected
DETAIL:  Process 31072 waits for ShareLock on transaction 124735679; blocked by process 30368.
Process 30368 waits for ShareLock on transaction 124735675; blocked by process 31072.
HINT:  See server log for query details.

update pref_users u
set medals = s.medals
from (
    select id, count(id) medals
    from (
        select id,
            row_number() over(partition by yw order by money desc) as ranking
        from pref_money where yw <> to_char(CURRENT_TIMESTAMP, 'IYYY-IW')
    ) x
    where ranking = 1
    group by id
) s
where u.id = s.id;

---

您可以创建一个使用奖牌选择的视图，并将其与实际数据关联：

CREATE VIEW pref_money_medals AS
SELECT *
FROM pref_money
JOIN (SELECT count(x.id)
      FROM (SELECT id, row_number() 
            OVER(PARTITION BY yw ORDER BY money DESC) AS ranking
            FROM pref_money
            ) x
      WHERE x.ranking = 1 group by x.id) medals
ON pref_money.id = medals.id;

---

奖牌是什么？这是每周获胜数吗？是的，没错。感谢大家关注我的问题，你多久做一次这个工作？我怀疑您正在尝试更新，而上一个更新仍在运行。那些桌子有多大？不相关，但您应该将这两个更新打包在一个事务中，否则归零的奖牌将立即可见。谢谢！我只需要添加更新pref_用户集。。。。其中u.id=s.id，因为pgsql正在抱怨列引用id为ambiguous@AlexanderFarber不使用'id'作为列标识符，而是通过示例为表pref\u money使用pref\u money\u id，这是一种很好的做法。这使得读取查询和允许自然连接变得更容易。@greg我建议只使用id。关于自然连接，我认为您是反向的。您可能知道我为什么会出现错误：检测到死锁？有关详细信息，请参阅我更新的问题

update pref_users u
set medals = s.medals
from (
    select id, count(id) medals
    from (
        select id,
            row_number() over(partition by yw order by money desc) as ranking
        from pref_money
    ) x
    where ranking = 1
    group by id
) s
where u.id = s.id