Sql 计算带OVER子句的运行总计和带计数器的按子句划分
如何使用计数器计算每周的点数和用户名? 我使用按顺序划分的和 我希望最大金额为10美元。 我该怎么做 这是我的原始表格: 以下是我希望得到的结果: 以下是sql代码:Sql 计算带OVER子句的运行总计和带计数器的按子句划分,sql,postgresql,sum,window-functions,Sql,Postgresql,Sum,Window Functions,如何使用计数器计算每周的点数和用户名? 我使用按顺序划分的和 我希望最大金额为10美元。 我该怎么做 这是我的原始表格: 以下是我希望得到的结果: 以下是sql代码: SELECT week_number, user_name, sum(points) OVER (PARTITION BY user_name ORDER BY week_number) AS total_prime FROM team; 试试这个 select week_number, user_name,
SELECT week_number,
user_name,
sum(points) OVER (PARTITION BY user_name ORDER BY week_number) AS total_prime
FROM team;
试试这个
select
week_number,
user_name,
points,
case when total_prime > 10 then 10 else total_prime end as sum,
case when total_prime > 1 and total_prime < 10 then null
when total_prime > 10 then total_prime - 10 end as dif
from
(select
week_number,
user_name, points,
sum(points) over (partition by user_name order by week_number) as total_prime
from
team) a
我在你的第二张桌子上看不到,艾伦有第4点,但有第2点 试试这个
select
week_number,
user_name,
points,
case when total_prime > 10 then 10 else total_prime end as sum,
case when total_prime > 1 and total_prime < 10 then null
when total_prime > 10 then total_prime - 10 end as dif
from
(select
week_number,
user_name, points,
sum(points) over (partition by user_name order by week_number) as total_prime
from
team) a
我在你的第二张桌子上看不到,艾伦有第4点,但有第2点