Sql 如何在vb.net中进行数据连接并在listview中显示
我是vb.net新手,谁能帮我创建一个连接并在listview中传输它。 例如: 表名userInfoSql 如何在vb.net中进行数据连接并在listview中显示,sql,vb.net,listview,join,inner-join,Sql,Vb.net,Listview,Join,Inner Join,我是vb.net新手,谁能帮我创建一个连接并在listview中传输它。 例如: 表名userInfo 用户ID fname 名字 表名accountInfo 用户ID 活跃 我想参加的是。。 用户ID 文件名 名字 活跃 然后在listview中传输 这是我的密码: Dim connincomeDivision As SqlConnection Dim cmdincomeDivision As SqlCommand Dim daincomeDivision As Sql
用户ID
fname
名字 表名accountInfo 用户ID 活跃 我想参加的是。。 用户ID 文件名 名字 活跃 然后在listview中传输 这是我的密码:
Dim connincomeDivision As SqlConnection
Dim cmdincomeDivision As SqlCommand
Dim daincomeDivision As SqlDataAdapter
Dim dsincomeDivision As DataSet
Dim itemcollincomeDivision(100) As String
connincomeDivision = New SqlConnection("Data Source =ENTITY-PC\SQLEXPRESS;Initial Catalog=chosenlandrealtyDB; integrated security = true;")
Dim strQincomeDivision As String = String.Empty
strQincomeDivision = "SELECT userID,fName,lName FROM userInfo JOIN account ON userInfo.userID = account.userID"
cmdincomeDivision = New SqlCommand(strQincomeDivision, connincomeDivision)
daincomeDivision = New SqlDataAdapter(cmdincomeDivision)
dsincomeDivision = New DataSet
daincomeDivision.Fill(dsincomeDivision, "userInfo")
Dim iincomeDivision As Integer = 0
Dim jincomeDivision As Integer = 0
' adding the columns in ListView
'Now adding the Items in Listview
For iincomeDivision = 0 To dsincomeDivision.Tables(0).Rows.Count - 1
For jincomeDivision = 0 To dsincomeDivision.Tables(0).Columns.Count - 1
itemcollincomeDivision(jincomeDivision) = dsincomeDivision.Tables(0).Rows(iincomeDivision)(jincomeDivision).ToString()
Next
Dim lviincomeDivision As New ListViewItem(itemcollincomeDivision)
Me.ListView2.Items.Add(lviincomeDivision)
Next
提前感谢:))