Sql 使用窗口功能统计销售额
我有一个疑问:Sql 使用窗口功能统计销售额,sql,sql-server,sql-server-2008,Sql,Sql Server,Sql Server 2008,我有一个疑问: USE AdventureWorks2012; GO SELECT CustomerID,COUNT(*) AS CountOfSales, COUNT(CustomerID) OVER (PARTITION BY CountOfSales) Total, RANK() OVER(ORDER BY COUNT(*) DESC) AS Ranking, ROW_NUMBER() OVER(ORDER BY COUNT(CustomerID) DESC) AS Row, DENSE
USE AdventureWorks2012;
GO
SELECT CustomerID,COUNT(*) AS CountOfSales,
COUNT(CustomerID) OVER (PARTITION BY CountOfSales) Total,
RANK() OVER(ORDER BY COUNT(*) DESC) AS Ranking,
ROW_NUMBER() OVER(ORDER BY COUNT(CustomerID) DESC) AS Row,
DENSE_RANK() OVER(ORDER BY COUNT(*)) AS DenseRanking
FROM Sales.SalesOrderHeader
GROUP BY CustomerID
ORDER BY COUNT(*) DESC;
这就得出了这个结果:
CustomerID CountOfSales Total Ranking Row DenseRanking
11091 28 1 1 2 17
11176 28 1 1 1 17
11200 27 1 3 9 16
11331 27 1 3 12 16
11287 27 1 3 5 16
11262 27 1 3 8 16
11276 27 1 3 11 16
11330 27 1 3 6 16
11711 27 1 3 13 16
11277 27 1 3 3 16
但现在我想有一个类似于total Countof Sales的列,所以:2加28,11加27
所以我的问题是如何管理
谢谢你如果我正确理解了你的问题,你可以将你的查询包装成一个子查询,并通过分区进行计数(*):
SELECT *, COUNT(*) OVER (PARTITION BY CountOfSales) AS total_countOfSales
FROM (
SELECT CustomerID,COUNT(*) AS CountOfSales,
COUNT(CustomerID) OVER (PARTITION BY CountOfSales) Total,
RANK() OVER(ORDER BY COUNT(*) DESC) AS Ranking,
ROW_NUMBER() OVER(ORDER BY COUNT(CustomerID) DESC) AS Row,
DENSE_RANK() OVER(ORDER BY COUNT(*)) AS DenseRanking
FROM Sales.SalesOrderHeader
GROUP BY CustomerID
) a
MySQL真的支持那些windows功能吗?11加27背后的逻辑是什么?因为只有9条记录的id为27。这只是查询结果的一部分。你的问题没有任何意义。。。当你用身份证要一笔钱的时候?COUNT()OVER(按Id分区)只希望有CountOfsales的总数。我的意思很清楚。