SQL自连接消除重复值

我必须选择不同的月份ID。下面的查询返回重复的值。如何解决这个问题

 SELECT DISTINCT m1.ID as C1, m2.ID as C2
    FROM Mois m1, Mois m2
    WHERE m1.ID IN('1','4','9')
    AND m2.ID IN('2','5','10')

这就是我想要的：

C1 | C2
1 | 2
4 | 5
9 | 10
输出

C1  C2
1   2
4   5
9   10

演示

尝试此选项：

WITH cte1 AS (
    SELECT DISTINCT m1.ID as C1, m2.ID as C2
    FROM Mois m1
    INNER JOIN Mois m2
    ON m1.ID IN (1, 4, 9) AND
       m2.ID IN (2, 5, 10) AND
       m1.ID < m2.ID
),
cte2 AS (
    SELECT C1, C2, ROW_NUMBER() OVER (PARTITION BY C1 ORDER BY C2) rn
    FROM cte1
)

SELECT C1, C2
FROM cte2
WHERE rn = 1
ORDER BY C1;

C1   C2
1   1   2
2   4   5
3   9   10

---

您期望的输出和示例数据是什么。没有重复项，至少两个ID列都没有。您的预期输出是什么？您需要有一种方法来聚合这些重复项c1=1，c2=2与c1=1不同，c2=3如何为c1值选择c2值？@TimBiegeleisen我希望每个列都包含不同的值这是一个很好的查询！非常感谢。这取决于你对“更好”一词的定义：-

C1  C2
1   2
4   5
9   10

WITH cte1 AS (
    SELECT DISTINCT m1.ID as C1, m2.ID as C2
    FROM Mois m1
    INNER JOIN Mois m2
    ON m1.ID IN (1, 4, 9) AND
       m2.ID IN (2, 5, 10) AND
       m1.ID < m2.ID
),
cte2 AS (
    SELECT C1, C2, ROW_NUMBER() OVER (PARTITION BY C1 ORDER BY C2) rn
    FROM cte1
)

SELECT C1, C2
FROM cte2
WHERE rn = 1
ORDER BY C1;

C1   C2
1   1   2
2   4   5
3   9   10