在SQL中查找连续行之间的年差异？

我试图根据指标id计算连续行之间的日期差异，以找出差异不超过3年的情况

year                             indicator_id
--------------------------      ---------------
January 1, 1999, 12:00 AM             1
January 1, 2000, 12:00 AM             1
January 1, 2001, 12:00 AM             1
January 1, 2006, 12:00 AM             1

我想得到的结果是

year                             indicator_id           Diff
--------------------------      ---------------        ------
January 1, 1999, 12:00 AM             1                  0
January 1, 2000, 12:00 AM             1                  1
January 1, 2001, 12:00 AM             1                  1
January 1, 2006, 12:00 AM             1                  5

我尝试了以下查询，但它只返回同一行，差为0

SELECT indicator_id, 
       year, 
       year - lag(year) over (order by year) as Diff
FROM education_data

请帮忙

找出差异不超过3年的案例

year                             indicator_id
--------------------------      ---------------
January 1, 1999, 12:00 AM             1
January 1, 2000, 12:00 AM             1
January 1, 2001, 12:00 AM             1
January 1, 2006, 12:00 AM             1

如果这是您想要的，则使用子查询获取外部查询中的上一个值和筛选器：

select ed.*
from (select ed.*, lag(year) over (order by year) as prev_year
      from education_data ed
     ) ed
where prev_year >= year - interval '3 year';

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我删除了不一致的数据库标记。请仅使用您真正使用的数据库进行标记。-这是你想要实现的吗？