一个月内每天的MSSQL总计

我正在尝试做一些与我以前问过的问题非常相似的事情，但我似乎无法让它正常工作。这是我先前的问题：

该表如下所示：

              Table Name: Totals
Date       |Program label   |count
           |                |    
2013-04-09 |Salary Day      |4364
2013-04-09 |Monthly         |6231
2013-04-09 |Policy          |3523
2013-04-09 |Worst Record    |1423
2013-04-10 |Salary Day      |9872
2013-04-10 |Monthly         |6543
2013-04-10 |Policy          |5324
2013-04-10 |Worst Record    |5432
2013-04-10 |Salary Day      |1245
2013-04-10 |Monthly         |6345
2013-04-10 |Policy          |5431
2013-04-10 |Worst Record    |5232

Date      |Salary Day |Monthly |Policy |Worst Record
2013-04-9 |23456      |63241   |23521  |23524
2013-04-10|45321      |72535   |12435  |83612

我的问题是：使用MSSQL 2008-是否有一种方法可以让我获得当月每个程序标签每天的总计数。正如你所看到的，有时它会一天运行两次。我需要能够解释这一点

输出应如下所示：

              Table Name: Totals
Date       |Program label   |count
           |                |    
2013-04-09 |Salary Day      |4364
2013-04-09 |Monthly         |6231
2013-04-09 |Policy          |3523
2013-04-09 |Worst Record    |1423
2013-04-10 |Salary Day      |9872
2013-04-10 |Monthly         |6543
2013-04-10 |Policy          |5324
2013-04-10 |Worst Record    |5432
2013-04-10 |Salary Day      |1245
2013-04-10 |Monthly         |6345
2013-04-10 |Policy          |5431
2013-04-10 |Worst Record    |5232

Date      |Salary Day |Monthly |Policy |Worst Record
2013-04-9 |23456      |63241   |23521  |23524
2013-04-10|45321      |72535   |12435  |83612

使用如下表运算符：

SELECT  *
FROM Totals AS t
PIVOT
(
   SUM(count)
   FOR [Program label] IN ([Salary Day], 
                           [Monthly], 
                           [Policy], 
                           [Worst Record])
) AS p;

在行动中看到它：

这将为您提供：

|       DATE | SALARY DAY | MONTHLY | POLICY | WORST RECORD |
-------------------------------------------------------------
| 2013-04-09 |       4364 |    6231 |   3523 |         1423 |
| 2013-04-10 |      11117 |   12888 |  10755 |        10664 |

试试这个-

SELECT 
    date
    , [Salary Day] = SUM(CASE when [Program label] = 'Salary Day' then COUNT end)
    , [Monthly] = SUM(CASE when [Program label] = 'Monthly' then COUNT end) 
    , [Policy] = SUM(CASE when [Program label] = 'Policy' then COUNT end) 
    , [Worst Record] = SUM(CASE when [Program label] = 'Worst Record' then COUNT end)  
FROM Totals
GROUP BY [Date];

试试这个

select Date,
  sum(case when [Program label] = 'Salary Day' then count else 0 end) [Salary Day],
  sum(case when [Program label] = 'Monthly' then count else 0 end) [Monthly],
  sum(case when [Program label] = 'Policy' then  count else 0 end) [Policy],
  sum(case when [Program label] = 'Worst Record' then count else 0 end) [Worst Record]
from Totals Group by [Date];

---

我使用了你的答案，因为它是最简单的，对我来说，即使我已经编辑了很多。谢谢。：）谢谢我从这件事中学到了一些新的东西：）非常有用的答案。我还没有选择使用它，因为我还没有完全适应它。虽然我肯定会用我未来的查询来测试这个。