Sql 如何按行和字段的具体值进行汇总

我必须对表运行查询，以获得每个特定字段值的总和。

rechargedate    originid
------------------------
2015-02-02      3
2015-02-02      3
2015-02-02      1
2015-02-02      1
2015-02-02      3
2015-02-02      2
2015-02-01      2
2015-02-01      3
2015-02-01      1
2015-02-01      1
2015-02-01      2

查询结果应该如下所示：

rechargedate    orig1   orig2   orig3
-------------------------------------
2015-02-02      2       1       3
2015-02-01      2       2       1

---

如何使用MS SQL 2008实现这一点？

您可以使用条件聚合：

CREATE TABLE #temp(
    RechargeDate    DATE,
    OriginID        INT
)
INSERT INTO #temp VALUES
('2015-02-02', 3),('2015-02-02', 3),('2015-02-02', 1),
('2015-02-02', 1),('2015-02-02', 3),('2015-02-02', 2),
('2015-02-01', 2),('2015-02-01', 3),('2015-02-01', 1),
('2015-02-01', 1),('2015-02-01', 2);

SELECT
    RechargeDate,
    orig1 = SUM(CASE WHEN OriginID = 1 THEN 1 ELSE 0 END),
    orig2 = SUM(CASE WHEN OriginID = 2 THEN 1 ELSE 0 END),
    orig3 = SUM(CASE WHEN OriginID = 3 THEN 1 ELSE 0 END)
FROM #temp
GROUP BY RechargeDate
ORDER BY RechargeDate DESC

DROP TABLE #temp

结果

RechargeDate orig1       orig2       orig3
------------ ----------- ----------- -----------
2015-02-02   2           1           3
2015-02-01   2           2           1

---

您可以使用条件聚合：

CREATE TABLE #temp(
    RechargeDate    DATE,
    OriginID        INT
)
INSERT INTO #temp VALUES
('2015-02-02', 3),('2015-02-02', 3),('2015-02-02', 1),
('2015-02-02', 1),('2015-02-02', 3),('2015-02-02', 2),
('2015-02-01', 2),('2015-02-01', 3),('2015-02-01', 1),
('2015-02-01', 1),('2015-02-01', 2);

SELECT
    RechargeDate,
    orig1 = SUM(CASE WHEN OriginID = 1 THEN 1 ELSE 0 END),
    orig2 = SUM(CASE WHEN OriginID = 2 THEN 1 ELSE 0 END),
    orig3 = SUM(CASE WHEN OriginID = 3 THEN 1 ELSE 0 END)
FROM #temp
GROUP BY RechargeDate
ORDER BY RechargeDate DESC

DROP TABLE #temp

结果

RechargeDate orig1       orig2       orig3
------------ ----------- ----------- -----------
2015-02-02   2           1           3
2015-02-01   2           2           1

---

最简单的方法是使用CASE语句创建所需的列，然后进行求和，例如

SELECT rechargedate,
     SUM(CASE WHEN originid = 1 THEN 1 ELSE 0 END) AS orig1,
     SUM(CASE WHEN originid = 2 THEN 1 ELSE 0 END) AS orig2,
     SUM(CASE WHEN originid = 3 THEN 1 ELSE 0 END) AS orig3
FROM {your_table}
GROUP BY rechargedate
ORDER BY rechargedate DESC

---

最简单的方法是使用CASE语句创建所需的列，然后进行求和，例如

SELECT rechargedate,
     SUM(CASE WHEN originid = 1 THEN 1 ELSE 0 END) AS orig1,
     SUM(CASE WHEN originid = 2 THEN 1 ELSE 0 END) AS orig2,
     SUM(CASE WHEN originid = 3 THEN 1 ELSE 0 END) AS orig3
FROM {your_table}
GROUP BY rechargedate
ORDER BY rechargedate DESC

---

使用

透视

。检查以了解

SQL SERVER中的
PIVIOT
。

SELECT rechargedate, 
       [1] AS orig1,
       [2] AS orig2,
       [3] AS orig3 
FROM #TEST
PIVOT(COUNT(originid) FOR originid IN([1],[2],[3])) AS Piv
ORDER BY rechargedate DESC

---

使用

透视

。检查以了解

SQL SERVER中的
PIVIOT
。

SELECT rechargedate, 
       [1] AS orig1,
       [2] AS orig2,
       [3] AS orig3 
FROM #TEST
PIVOT(COUNT(originid) FOR originid IN([1],[2],[3])) AS Piv
ORDER BY rechargedate DESC

---

到目前为止，嘟嘟尝试了什么？到目前为止，嘟嘟尝试了什么？谢谢你，伊万夫，很接近，但不完全如此。这也是我的解决方案。我在结果集中得到了一些零。谢谢你，evanv，很接近，但不完全一样。这也是我的解决方案。我在结果集中得到了一些零。太棒了！这正是我想要的，而且很简单。非常感谢。太棒了！这正是我想要的，而且很简单。非常感谢。谢谢你，库马尔，我尝试了Wewe解决方案，因为它与我所尝试的类似，工作起来很有魅力。我感谢你的时间。谢谢你，库马尔，我尝试了Wewe解决方案，因为它与我所尝试的类似，工作起来很有魅力。谢谢你抽出时间。