SQL合并重叠时间间隔

我有这样一个sqlite数据集

Startdate  | Enddate    | ID 
2019-04-29 | 2019-05-04 | 12
2019-04-23 | 2019-04-25 | 533
2019-04-23 | 2019-04-24 | 44
2019-04-24 | 2019-04-25 | 79

我试图得到一个从startdate到startdate再加上循环中直到最后一个EndDate的范围内排序的输出。 计划是获取从minStartdate到minStartdate+1和minStartdate+2的所有观测值，依此类推

Range                 | ID
2019-04-23 2019-04-24 | 44
2019-04-23 2019-04-25 | 44
2019-04-23 2019-04-25 | 533
2019-04-23 2019-04-25 | 79
2019-04-23 2019-05-04 | 44
2019-04-23 2019-05-04 | 533
2019-04-23 2019-05-04 | 79
2019-04-23 2019-05-04 | 12

---

我不确定是否必须实现这一点

我相信以下内容将提供您想要的结果：-

WITH cte(sdate,edate) AS 
    (
        SELECT (SELECT min(startdate) FROM mytable),(SELECT min(startdate) FROM mytable)
        UNION ALL 
            SELECT sdate,date(edate,'+1 days') 
            FROM cte 
            WHERE edate <= (
                SELECT max(enddate) FROM mytable
            ) 
            LIMIT 1000 /* just in case limit to 1000 rows */
    )
SELECT sdate||' '||edate AS Range, id 
FROM cte 
    JOIN mytable ON startdate >= sdate 
        AND enddate <= edate 
        AND edate IN (SELECT enddate FROM mytable)

示例/测试/演示 结果是：-

唯一的区别是ID列的顺序，我看不到与预期结果的任何顺序 根据注释限制，不需要1000

DROP TABLE IF EXISTS mytable;
CREATE TABLE IF NOT EXISTS mytable (startdate TEXT, enddate TEXT, id INTEGER PRIMARY KEY);
INSERT INTO mytable VALUES
    ('2019-04-29','2019-05-04',12),
    ('2019-04-23','2019-04-25',533),
    ('2019-04-23','2019-04-24',44),
    ('2019-04-24','2019-04-25',79)
;
WITH cte(sdate,edate) AS 
    (
        SELECT (SELECT min(startdate) FROM mytable),(SELECT min(startdate) FROM mytable)
        UNION ALL 
            SELECT sdate,date(edate,'+1 days') 
            FROM cte 
            WHERE edate <= (
                SELECT max(enddate) FROM mytable
            ) 
            LIMIT 1000 /* just in case limit to 1000 rows */
    )
SELECT sdate||' '||edate AS Range, id 
FROM cte 
    JOIN mytable ON startdate >= sdate 
        AND enddate <= edate 
        AND edate IN (SELECT enddate FROM mytable)
;
DROP TABLE IF EXISTS mytable;