Sql 博士后为何获胜'；t正确映射列

我有此查询要更新另一个表，但出现错误

With CTE AS
(Select employer_id, employee_id, start_date, end_date, hourly_rate, end_date - start_date AS time_worked
 FROM payroll_timesheet)
INSERT INTO payroll_timelog 
SELECT * FROM CTE
WHERE employee_id = 1;

我得到这个错误：

ERROR:  column "employee_id" is of type integer but expression is of type timestamp with time zone
LINE 5: SELECT employer_id, employee_id, start_date, end_date, hourl...
                                         ^
HINT:  You will need to rewrite or cast the expression.

它似乎将

员工id

映射为

开始日期

---

或者查询中是否存在语法错误？

您当前的错误是一个很好的理由，可以解释为什么您应该始终在insert中显式列出目标表的列名。您应该使用类似以下内容：

WITH cte AS (
    SELECT employer_id, employee_id, start_date, end_date, hourly_rate,
           end_date - start_date AS time_worked
    FROM payroll_timesheet
)

INSERT INTO payroll_timelog (employer_id, employee_id, start_date, end_date, hourly_rate,
                             time_worked)
SELECT employer_id, employee_id, start_date, end_date, hourly_rate, time_worked
FROM cte
WHERE employee_id = 1;

---

您可能需要更改目标

payroll\u timelog

表的列名以匹配。发生当前错误是因为Postgres使用默认列顺序，而您没有指定所需的列顺序。

您当前的错误是一个很好的理由，可以解释为什么您应该始终在insert中显式列出目标表的列名。您应该使用类似以下内容：

WITH cte AS (
    SELECT employer_id, employee_id, start_date, end_date, hourly_rate,
           end_date - start_date AS time_worked
    FROM payroll_timesheet
)

INSERT INTO payroll_timelog (employer_id, employee_id, start_date, end_date, hourly_rate,
                             time_worked)
SELECT employer_id, employee_id, start_date, end_date, hourly_rate, time_worked
FROM cte
WHERE employee_id = 1;

您可能需要更改目标

payroll\u timelog

表的列名以匹配。发生当前错误是因为Postgres使用默认列顺序，而您没有指定所需的列顺序