SQL选择两个日期之间重复次数最多的行
我有三张桌子:借书台和客户台SQL选择两个日期之间重复次数最多的行,sql,ms-access,Sql,Ms Access,我有三张桌子:借书台和客户台 书籍(Id、标题等) 借方(BookID、客户ID、借款日期等) 客户机(Id、名称等) 我需要返回的SQL查询 在两个日期之间被出租的书。 日期将作为参数传递给查询。这如何 SELECT * FROM Books INNER JOIN Debit ON Books.Id = Debit.BooksID WHERE BorrowingDate >= @StartDate AND BorrowingDate <= @EndDate SELECT*FROM
SELECT * FROM Books INNER JOIN Debit ON Books.Id = Debit.BooksID WHERE BorrowingDate >= @StartDate AND BorrowingDate <= @EndDate
SELECT*FROM Books internal JOIN Debit ON Books.Id=Debit.BooksID其中brookingdate>=@StartDate和brookingdate=@StartDate和brookingdate查询
SELECT TOP 1 *
FROM (
SELECT BooksID, COUNT(*) AS C
FROM Debit
WHERE BorrowingDate BETWEEN @min_date and @max_date
GROUP BY BooksID
)
ORDER BY C DESC
…将生成一行,其中包含图书ID
和在@min\u date
和@max\u date
之间租赁次数最多的图书的租金数
如果您需要的不仅仅是BooksID
,而且您还尝试了什么?+1因为尽管我们得出了几乎相同的答案,但您已经向我介绍了介于之间的操作员!这正是我想要的。非常感谢你。
SELECT TOP 1 *
FROM (
SELECT BooksID, COUNT(*) AS C
FROM Debit
WHERE BorrowingDate BETWEEN @min_date and @max_date
GROUP BY BooksID
)
ORDER BY C DESC