如何获得SQL格式的输出

我有这样的SQL表

Column_TEAM
AUS
USA
IND
RUS

预期结果是一支球队只能和另一支球队比赛一次

AUS vs USA
AUS vs IND
AUS vs RUS
USA vs IND
USA vs RUS
IND vs RUS

我试着用排名函数进行排名，但没有成功。

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请在SQL Server或PostgreSQL中帮助我，您需要按如下方式自行加入您的表：

-- SQL Server concatenation syntax
SELECT a.Column_TEAM + ' vs ' + b.Column_TEAM
FROM my_table a
JOIN my_table b ON a.Column_TEAM < b.Column_TEAM

-- PostgreSQL concatenation syntax
SELECT a.Column_TEAM || ' vs ' || b.Column_TEAM
FROM my_table a
JOIN my_table b ON a.Column_TEAM < b.Column_TEAM

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您需要按如下方式自联接表：

-- SQL Server concatenation syntax
SELECT a.Column_TEAM + ' vs ' + b.Column_TEAM
FROM my_table a
JOIN my_table b ON a.Column_TEAM < b.Column_TEAM

-- PostgreSQL concatenation syntax
SELECT a.Column_TEAM || ' vs ' || b.Column_TEAM
FROM my_table a
JOIN my_table b ON a.Column_TEAM < b.Column_TEAM

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您也可以使用简单的内部联接来完成。给你

SELECT T2.CTRY2,T1.CTRY1
FROM 
(SELECT CTRY AS CTRY1,ROW_NUMBER() OVER(ORDER BY CTRY) AS R1 FROM (VALUES ('AUS'),('USA'),('IND'),('RUS') ) CT (CTRY)) T1

JOIN 

(SELECT CTRY AS CTRY2,ROW_NUMBER() OVER(ORDER BY CTRY) AS R2 FROM (VALUES ('AUS'),('USA'),('IND'),('RUS') ) CT (CTRY)) T2

ON T1.R1 > T2.R2
ORDER BY T1.CTRY1 ASC

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您也可以使用简单的内部联接来完成。给你

SELECT T2.CTRY2,T1.CTRY1
FROM 
(SELECT CTRY AS CTRY1,ROW_NUMBER() OVER(ORDER BY CTRY) AS R1 FROM (VALUES ('AUS'),('USA'),('IND'),('RUS') ) CT (CTRY)) T1

JOIN 

(SELECT CTRY AS CTRY2,ROW_NUMBER() OVER(ORDER BY CTRY) AS R2 FROM (VALUES ('AUS'),('USA'),('IND'),('RUS') ) CT (CTRY)) T2

ON T1.R1 > T2.R2
ORDER BY T1.CTRY1 ASC

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@Ananda SteelTownBoy你也可以使用交叉连接，我猜这对你来说也是新的；a队和b队在哪里_TEAM@Ananda-是的，加入是一个有趣的话题@Ananda SteelTownBoy你也可以使用交叉连接，我猜这对你来说也是新的；a队和b队在哪里_TEAM@Ananda-是的，加入是一个有趣的话题。