选定案例中的SQL最小值和最大值关系

我正在使用以下代码从SQL表中检索列-

MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.ID ELSE NULL END) "MondayHourlyAM",                 
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN s.SchoolName ELSE NULL END) "MondayHourlyAMSchoolName",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN REPLACE(REPLACE(LTRIM(RIGHT(CONVERT(VARCHAR, bd.StartTime, 100), 7)) + '-' + LTRIM(RIGHT(CONVERT(VARCHAR(20), bd.EndTime, 100), 7)), 'AM',''), 'PM', '') ELSE NULL END) "MondayHourlyAMTimes",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalChargeAmount ELSE NULL END) "MondayHourlyAMTotalChargeAmount",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalPayAmount ELSE NULL END) "MondayHourlyAMTotalPayAmount",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.BandBookedAt ELSE NULL END) "MondayHourlyAMBandBookedAt",

            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.ID ELSE NULL END) "MondayHourlyAM2",                    
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN s.SchoolName ELSE NULL END) "MondayHourlyAM2SchoolName",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN REPLACE(REPLACE(LTRIM(RIGHT(CONVERT(VARCHAR, bd.StartTime, 100), 7)) + '-' + LTRIM(RIGHT(CONVERT(VARCHAR(20), bd.EndTime, 100), 7)), 'AM',''), 'PM', '') ELSE NULL END) "MondayHourlyAM2Times",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalChargeAmount ELSE NULL END) "MondayHourlyAM2TotalChargeAmount",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalPayAmount ELSE NULL END) "MondayHourlyAM2TotalPayAmount",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.BandBookedAt ELSE NULL END) "MondayHourlyAM2BandBookedAt",

MAX（bd.DayText='Monday'和bd.BookingDuration=3，CONVERT（time（0），bd.StartTime）

当此代码运行时，我得到了2个预订，但是返回的收费/付款率是针对其他预订的。即-

应该是 预订1-收费20英镑，付款10英镑 预订2-收费100英镑，付款50英镑

但是我越来越 预订1-收费100英镑，付款50英镑 预订2-收费20英镑，付款10英镑

我想这是因为当我使用MAX和MIN时，它会返回最高值和最低值。我如何将返回的MAX和MIN值与“HourlyAM”列相关联

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希望我能很好地解释这一点！谢谢

我不会在不更好地理解您的数据的情况下尝试通过您的标准，但我认为使用行号（）会更好：

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这里的想法是，您根据一个字段为符合条件的每一行分配一个排名，然后根据该排名返回整行。

鉴于几乎所有case语句都具有相同的逻辑，您确实应该将公共子句从case中移出，并移到查询的主

where

子句中。这是一个小部分一周中的每一天都有6个段落，相似但持续时间不同（即：上午、下午、全天、上午每小时、下午每小时、全天每小时）.我意识到这不是最有效的方法，但它似乎工作得很好，而且速度很快。因此，我认为我无法将常用子句移到主要where子句中。干杯

SELECT *
FROM ( SELECT *, ROW_NUMBER() OVER (ORDER BY MondayHourlyAMTimes DESC) 'Booking1'
               , ROW_NUMBER() OVER (ORDER BY MondayHourlyAMTimes ) 'Booking2'
       FROM Table
       WHERE common criteria
     )
WHERE Booking1 = 1 OR Booking2 = 1