Sql 使用不同的where子句条件组合查询

如何组合这些查询，以便使用第一个查询中第二个查询的

dayCall

第一次查询

select clientid, 
DATEDIFF(
        DAY,
        CONVERT(datetime, convert(varchar(10), min(calendar))),
        MIN(dayCall)     
        )
from
Stats 
group by clientid

SELECT  
    clientid, 
    MIN(calendar)    
    as dayCall
FROM (
    SELECT 
        clientid, 
        CONVERT(datetime, convert(varchar(10), calendar)) calendar,
        lead(calls) over (partition by clientid order by calendar) as total_1,
        lead(calls, 2) over (partition by clientid order by calendar) as total_2
    FROM STATS

) a
where calls = 0 and total_1 = 0 and total_2 = 0
GROUP BY clientid

第二次查询

select clientid, 
DATEDIFF(
        DAY,
        CONVERT(datetime, convert(varchar(10), min(calendar))),
        MIN(dayCall)     
        )
from
Stats 
group by clientid

SELECT  
    clientid, 
    MIN(calendar)    
    as dayCall
FROM (
    SELECT 
        clientid, 
        CONVERT(datetime, convert(varchar(10), calendar)) calendar,
        lead(calls) over (partition by clientid order by calendar) as total_1,
        lead(calls, 2) over (partition by clientid order by calendar) as total_2
    FROM STATS

) a
where calls = 0 and total_1 = 0 and total_2 = 0
GROUP BY clientid

---

你可以把这些表连在一起。我看到clientID在这两个表中都很常见，但应该进行完全外部联接，以确保即使两个表之间没有公共clientID，也能得到所有结果：

SELECT * FROM 
(
select clientid, 
DATEDIFF(
        DAY,
        CONVERT(datetime, convert(varchar(10), min(calendar))),
        MIN(dayCall)     
        )
from
Stats 
group by clientid
) tableA
FULL OUTER JOIN 
(
SELECT  
    clientid, 
    MIN(calendar)    
    as dayCall
FROM (
    SELECT 
        clientid, 
        CONVERT(datetime, convert(varchar(10), calendar)) calendar,
        lead(calls) over (partition by clientid order by calendar) as total_1,
        lead(calls, 2) over (partition by clientid order by calendar) as total_2
    FROM STATS

) a
where calls = 0 and total_1 = 0 and total_2 = 0
GROUP BY clientid
) tableB
ON tableA.clientid = tableB.clientid

---

你可以把这些表连在一起。我看到clientID在这两个表中都很常见，但应该进行完全外部联接，以确保即使两个表之间没有公共clientID，也能得到所有结果：

SELECT * FROM 
(
select clientid, 
DATEDIFF(
        DAY,
        CONVERT(datetime, convert(varchar(10), min(calendar))),
        MIN(dayCall)     
        )
from
Stats 
group by clientid
) tableA
FULL OUTER JOIN 
(
SELECT  
    clientid, 
    MIN(calendar)    
    as dayCall
FROM (
    SELECT 
        clientid, 
        CONVERT(datetime, convert(varchar(10), calendar)) calendar,
        lead(calls) over (partition by clientid order by calendar) as total_1,
        lead(calls, 2) over (partition by clientid order by calendar) as total_2
    FROM STATS

) a
where calls = 0 and total_1 = 0 and total_2 = 0
GROUP BY clientid
) tableB
ON tableA.clientid = tableB.clientid

---

使用条件聚合：

select clientid, 
       min(case when calls = 0 and total_1 = 0 and total_2 = 0 then calendar end) as dayCall,
       datediff(day
                convert(datetime, convert(varchar(10), min(calendar))),
                min(dayCall)     
               )
from (select s.*, 
             convert(datetime, convert(varchar(10), calendar)) calendar,
                     lead(calls) over (partition by clientid order by calendar) as total_1,
                     lead(calls, 2) over (partition by clientid order by calendar) as total_2
      from STATS s
     ) s
group by clientid

---

使用条件聚合：

select clientid, 
       min(case when calls = 0 and total_1 = 0 and total_2 = 0 then calendar end) as dayCall,
       datediff(day
                convert(datetime, convert(varchar(10), min(calendar))),
                min(dayCall)     
               )
from (select s.*, 
             convert(datetime, convert(varchar(10), calendar)) calendar,
                     lead(calls) over (partition by clientid order by calendar) as total_1,
                     lead(calls, 2) over (partition by clientid order by calendar) as total_2
      from STATS s
     ) s
group by clientid

---

对你的大多数读者来说，这可能是苹果对橙子。最好在这里包含一些示例数据以及预期的输出。第二个查询无效。应引发错误。请使用CTE（公共表表达式）计算第二个查询，然后在第一个查询中使用它。对于大多数读者来说，这可能是小菜一碟。最好在这里包含一些示例数据以及预期的输出。第二个查询无效。应引发错误。使用CTE（公共表表达式）计算第二个查询，然后在第一个查询中使用它。当尝试执行

MIN（dayCall）

时，我收到

无效列名dayCall

错误。原始查询可能有问题。我所做的只是按照请求将这两个查询连接在一起。我没有测试您的原始查询。我在尝试执行

MIN（dayCall）

时遇到

无效列名dayCall

错误。您的原始查询可能有问题。我所做的只是按照请求将这两个查询连接在一起。我没有测试您的原始查询。我在尝试执行

MIN（dayCall）

@Aaron时遇到

无效列名dayCall

错误

DayCall

在您的第一个查询中。这不是我发明的。我编辑了答案，从

STATS

中选取了所有栏目。戈登，我想我之前不清楚。此行抛出错误-

datediff（day convert（日期时间，convert（varchar（10），min（日历））），min（dayCall））

。它无法从脚本的第二行识别

dayCall

。当它尝试执行

MIN（dayCall）

@Aaron时，我得到一个

无效的列名dayCall

错误

DayCall

在您的第一个查询中。这不是我发明的。我编辑了答案，从

STATS

中选取了所有栏目。戈登，我想我之前不清楚。此行抛出错误-

datediff（day convert（日期时间，convert（varchar（10），min（日历））），min（dayCall））

。它无法从脚本的第二行识别

dayCall

。