sqlite中的分组行未按预期工作

因此，我想对所有标题相同的文章进行分组：

CREATE TABLE Article(
    ID INTEGER NOT NULL,
    Title TEXT
);
CREATE TABLE Tag(
    ID INTEGER NOT NULL,
    Name TEXT
);
CREATE TABLE Article_Tag(
    Article_ID INTEGER NOT NULL,
    Tag_ID INTEGER NOT NULL,
    PRIMARY KEY (Article_ID,Tag_ID)
); 
INSERT INTO Article (ID, Title) VALUES
(1,  'wifi'),
(2,  'bluetooth'),
(3,  'firewire');
INSERT INTO Tag (ID, Name) VALUES
(1,  'tag 1'),
(2,  'tag 2'),
(3,  'tag 3');
INSERT INTO Article_Tag (Article_ID, Tag_ID) VALUES
(1,  1),
(1,  2),
(1,  3),
(2,  1);
--------------------------------------
SELECT
  a.Title,  
  t.Name AS TagName
FROM Article AS a
  LEFT OUTER JOIN Article_Tag AS a_t ON a.ID = a_t.Article_ID
  LEFT OUTER JOIN Tag t ON t.ID = a_t.Tag_ID  
--------------------------------------
Title           TagName
wifi            tag 1
wifi            tag 2
wifi            tag 3
bluetooth       tag 1
firewire        (null)

但我想要这个：

SELECT
  a.Title,  
  GROUP_CONCAT(t.Name,';') AS TagNames
FROM Article AS a
  LEFT OUTER JOIN Article_Tag AS a_t ON a.ID = a_t.Article_ID
  LEFT OUTER JOIN Tag t ON t.ID = a_t.Tag_ID
--------------------------------------
Title       TagNames
firewire    tag 1;tag 2;tag 3;tag 1

---

我做错了什么？

只需添加一个

GROUPBY

子句

Title       TagNames
wifi        tag 1; tag 2; tag3
bluetooth   tag 1;
firewire    (null)

---

若要以相同的顺序获得相同的结果，请添加“a.id分组”广告，如下所示：

SELECT
  a.Title,  
  GROUP_CONCAT(t.Name,';') AS TagNames
FROM Article AS a
  LEFT OUTER JOIN Article_Tag AS a_t ON a.ID = a_t.Article_ID
  LEFT OUTER JOIN Tag t ON t.ID = a_t.Tag_ID
group by a.title

此处演示：

---

因为你应该根据问题

得到每个标题一行，我想对所有标题相同的文章进行分组

啊，我明白了，没有这一点，sqlite就不知道如何对

group\u concat

请求的

t.Name

列进行分组。很有道理。

SELECT
  a.Title,  
  GROUP_CONCAT(t.Name,';') AS TagNames
FROM Article AS a
  LEFT OUTER JOIN Article_Tag AS a_t ON a.ID = a_t.Article_ID
  LEFT OUTER JOIN Tag t ON t.ID = a_t.Tag_ID
group by a.id