Sql 空行'；由于分组联接表而存在

我正在与

groupby

和

Null

斗争，如下所示

我有两张像下面这样的桌子

Table : 1 accountmast       
companyID   accname             category    
102         PURCHASE ACCOUNT    Purchase Account    
102         LOCAL PURCHASE      Purchase Account    
102         SALES ACCOUNT       Sales Account   

Table: 2 ledger     
companyID   name                debit   credit
102         PURCHASE ACCOUNT    4742.3  
102         LOCAL PURCHASE      51106   
102         SALES ACCOUNT               8010
102         SALES ACCOUNT               4330000
102         PURCHASE ACCOUNT    5480000 

我的问题如下：

select  
case    
when a.catagory ='Purchase Account' then    
l.name  
end as PurchaseAccount, 

case    
when a.catagory ='Purchase Account' then    
sum(coalesce(l.debit,0))-sum(coalesce(l.credit,0) ) 
end as PurAmt,  

case    
when a.catagory = 'Sales Account' then  
l.name      
end as SalesAccount,    
case    
when a.catagory = 'Sales Account' then  
sum(coalesce(l.credit,0))-sum(coalesce(l.debit,0) ) 
end as SalesAmt 

from ledger l join accountmast a    
on l.companyID=a.companyID  
and l.name = a.accname  
where l.companyID=102   
and a.catagory IN('Purchase Account','Sales Account')   
group by l.name,a.catagory  

结果是：

Purchase Account    PurAmt          Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         NULL           NULL
PURCHASE ACCOUNT    5484742.30       NULL           NULL
NULL                NULL            SALES ACCOUNT  4338010.00

要求是：

Purchase Account    PurAmt           Sales Account   SalesAmt
LOCAL PURCHASE      51106.00         SALES ACCOUNT   4338010.00
PURCHASE ACCOUNT    5484742.30      

解决办法是什么

如果使用

groupby

，则允许

Null

值关联表的列

如果我使用

MAX

，

MIN

，那么它会显示单个记录。我该怎么办

---

如果有人有更好的解决方案，请提出。

注意：这不是一个答案，而是供参考。

WITH    q AS
        (
        SELECT  am.category, l.name,
                CASE am.category WHEN 'Purchase Account' THEN amt ELSE -amt END
        FROM    accountmast am
        CROSS APPLY
                (
                SELECT  name, SUM(COALESCE(credit, 0) - COALESCE(debit, 0)) AS amt
                FROM    ledger l
                WHERE   l.name = am.accname
                        AND l.companyId = am.companyId
                GROUP BY
                        name
                ) l
        WHERE   am.companyId = 102
        )
SELECT  l1.name, l1.amt, l2.name, l2.amt
FROM    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Purchase account'
        ) l1
FULL JOIN
        (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   category = 'Sales account'
        ) l2
ON      l2.rn = l1.rn

这里我作了一些更正，供你考虑

WITH    q AS
(
SELECT  am.catagory, l.name,
CASE am.catagory WHEN 'Purchase Account' THEN Amount ELSE -Amount     END as Amount -- Here I provide the column name and alter the Column
FROM    accountmast am
    CROSS APPLY
    (
    SELECT  name, SUM(COALESCE(debit, 0) - COALESCE(credit, 0)) AS Amount --Reverse the sum function which is oppose of yours. And your's shows the value in minus.
    FROM    ledger l
    WHERE   l.name = am.accname
    AND l.companyId = am.companyId
    GROUP BY
             name
    ) l
    WHERE   am.companyId = 102
)
SELECT  l1.name as PurACC, l1.Amount as PurAmt, l2.name as SalACC, l2.Amount as SalAmt -- alter the columns for Binding Purpose.
FROM
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Purchase account'
    ) l1
FULL JOIN
    (
        SELECT  *, ROW_NUMBER() OVER (ORDER BY name) AS rn
        FROM    q
        WHERE   catagory = 'Sales account'
    ) l2
ON l2.rn = l1.rn

---

以上更改很重要，否则您的答案仍然不正确并抛出错误检查。

SQL将返回一个表-您希望在第四个位置做什么？每隔一个单词大写一次非常重要。@Mark，对不起，我没有得到第四个位置，哪一个第四个位置？@Mark，如果没有值，则为null elsevalue@Quassnoi,我没有明白你的意思。有一个错误“没有为q的第3列指定列”，你必须在“CASE am.category”行中指定列名称，如“amt”，当“Purchase Account”时，然后是amt ELSE-amt END“as amt”。你的查询显示的销售金额数字与采购金额数字相同。它没有显示sum（）好的，关于专栏。它更正了您在MS Sql-2008中的查询，但我使用的是Sql-2005，Sql-2005没有选项。您对ms sql-2008的更正查询在我的sql-2005上没有返回任何内容，返回空值，我很困惑？。否则，您建议的链接将非常有用。@mahesh:查询将在两个引擎上的相同数据上返回相同的值。将小提琴复制到

2005

并查看。这里我提供了新的帖子供您参考。