Sql 分组时使用XML路径操作行数据

在sql查询中，我尝试做两件事

我有一张这样的桌子

桌子

EID-雇员ID

PID-点ID位置

D-白班

夜班

当我按除Shift以外的所有字段进行分组时，当仅对In_时间字段的日期部分进行分组时，我希望得到此值

中间步骤

最后，我想将其旋转以获得以下结果

预期最终结果

我在这里使用以下查询，但得到的结果略有不同

SELECT EID AS EmployeeID, [1],[2],[3],[4] 
FROM (

SELECT 
  EID, datepart(dd,in_time) as [DAY],
  STUFF((
    SELECT '/ ' + Shift  
    FROM Attendance  
    WHERE ([in_time] = Results.[in_time] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS Shifts 
FROM Attendance Results 
WHERE EID = '100' AND PID ='C002' 
GROUP BY EID , in_time
) AS SourceTable 

 PIVOT
 (
 MAX (Shifts ) 
 FOR [DAY] IN ( [1],[2],[3],[4])
 ) AS PivotTable

这是查询的结果

   EmployeeID | 01 | 02 | 03 | 04  |
   ________________________________
   100        |  D | _  | _  | N/N |

我的问题有点不对劲，你能帮我解决一下吗？我在这个查询中遗漏了什么？你知道更好的方法吗

编辑：我刚刚意识到，只要考勤表包含与单个员工和单点PID相关的记录，上述代码就可以正常工作

---

如果上表包含在不同PIDs位置工作的多个员工EIDs的详细信息，则输出是错误的。因此，我看到代码不一致，但我的sql知识似乎不足以在没有帮助的情况下解决这个问题：

下面的答案可能会对您有所帮助。SQL看起来很长，但逻辑很简单，只需将D和N数据分组并最终合并。也许你可以从这里开始工作

DECLARE @Lu_Dt table
(id int identity(1,1),Dt Date)
INSERT INTO @Lu_Dt VALUES('2014-05-01'),
('2014-05-02'),('2014-05-03'),
('2014-05-04'),('2014-05-05')

DECLARE @tab table
(EID int,PID varchar(15),In_Time datetime,Out_Time datetime,[Shift] Char(1))
INSERT INTO @tab Values
(100,'S001','2014-05-01 07:10','2014-05-01 19:20','D'),
(100,'S001','2014-05-04 07:00','2014-05-04 19:00','D'),
(100,'S001','2014-05-04 19:00','2014-05-05 07:00','N')

SELECT * FROM @tab

结果

---

因为有很多硬编码，所以不能这样使用。希望这能有所帮助。

Out\u Time=2014-05-05 07:00怎么样。它不会显示在您想要的结果中。你只是把准时视为员工的工作日吗？@Jithin Shaji，是的，轮班属于准时日。所以我不想出去玩了。Out_Time将只用于分类shiftsI删除了一些不需要的东西，使其更简单非常感谢。这有帮助。如果你不介意的话，你能解释一下代码的第二部分是以INSERT INTO@refTab开头的。。。这将非常有帮助。我将结果保存到临时表@refTab中，这样编写PIVOT语句看起来就不那么复杂了。

SELECT EID AS EmployeeID, [1],[2],[3],[4] 
FROM (

SELECT 
  EID, datepart(dd,in_time) as [DAY],
  STUFF((
    SELECT '/ ' + Shift  
    FROM Attendance  
    WHERE ([in_time] = Results.[in_time] ) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS Shifts 
FROM Attendance Results 
WHERE EID = '100' AND PID ='C002' 
GROUP BY EID , in_time
) AS SourceTable 

 PIVOT
 (
 MAX (Shifts ) 
 FOR [DAY] IN ( [1],[2],[3],[4])
 ) AS PivotTable

   EmployeeID | 01 | 02 | 03 | 04  |
   ________________________________
   100        |  D | _  | _  | N/N |

DECLARE @Lu_Dt table
(id int identity(1,1),Dt Date)
INSERT INTO @Lu_Dt VALUES('2014-05-01'),
('2014-05-02'),('2014-05-03'),
('2014-05-04'),('2014-05-05')

DECLARE @tab table
(EID int,PID varchar(15),In_Time datetime,Out_Time datetime,[Shift] Char(1))
INSERT INTO @tab Values
(100,'S001','2014-05-01 07:10','2014-05-01 19:20','D'),
(100,'S001','2014-05-04 07:00','2014-05-04 19:00','D'),
(100,'S001','2014-05-04 19:00','2014-05-05 07:00','N')

SELECT * FROM @tab

DECLARE @refTab table
(id int identity(1,1),EID int, Dt Date,[shift] varchar(3))

INSERT INTO @refTab

SELECT      Lu.EID,Lu.Dt,coalesce(LU1.[Flag],LU2.[Flag]) [shift]
FROM        (SELECT *,100 EID FROM @Lu_Dt) Lu
LEFT JOIN   (SELECT D.EID,D.In_Time,'D/N' [Flag]
            FROM    (SELECT EID,CAST(In_Time AS DATE) In_Time FROM @tab Where Shift = 'D') D
            JOIN    (SELECT EID,CAST(In_Time AS DATE) In_Time FROM @tab Where Shift = 'N') N 
            ON      D.In_Time = N.In_Time AND D.EID = N.EID) LU1 ON Lu.Dt = LU1.In_Time
LEFT JOIN   (SELECT CAST(In_Time AS DATE) In_Time,'D' [Flag] FROM @tab Where Shift = 'D') LU2 ON Lu.Dt = LU2.In_Time
LEFT JOIN   (SELECT CAST(In_Time AS DATE) In_Time,'N' [Flag] FROM @tab Where Shift = 'N') LU3 ON Lu.Dt = LU3.In_Time

SELECT * FROM @refTab

SELECT  *
FROM    (SELECT EID,Dt,[shift] from @refTab) As src 
PIVOT
(MAX([shift]) for Dt in 
    (   [2014-05-01],
        [2014-05-02],
        [2014-05-03],
        [2014-05-04],
        [2014-05-05])) AS PivotTable;