用于生成列值的SQL语句

请参见下面的DDL：

 create table Person (ID int, [Type] int)
 insert into Person values (1,1)
 insert into Person values (2,1)
 insert into Person values (3,2)
 insert into Person values (4,3)
 insert into Person values (5,4)
 insert into Person values (6,5)

我在寻找这样的结果：

2 1 1 1 1

以下条件生成此结果：

There are 2 persons with a type of 1 (The first column value is: 2)
There is 1 person with a type of 2 (The second column value is: 1)
There is 1 person with a type of 3 (The third column value is: 1)
There is 1 person with a type of 4 (The forth column value is: 1)
There is 1 person with a type of 5 (The fifth column value is: 1)

---

使用

CASE

来

SUM

不同类型的

select sum(case when [Type] = 1 then 1 else 0 end),
       sum(case when [Type] = 2 then 1 else 0 end),
       sum(case when [Type] = 3 then 1 else 0 end),
       sum(case when [Type] = 4 then 1 else 0 end),
       sum(case when [Type] = 5 then 1 else 0 end)
from tablename

---

如果你想让info_消息在只有1个计数的情况下切换到is，那么我可以这样做，但这需要我认为不必要的case逻辑。但这取决于你。如果你想让我改变它，请告诉我

DECLARE @Cnt_list VARCHAR(MAX) =
                                    (
                                    SELECT CAST(COUNT(*) AS VARCHAR(10)) + ' '
                                    FROM Person
                                    GROUP BY [Type]
                                    ORDER BY [Type]
                                    FOR XML PATH('')
                                    )
SELECT @Cnt_list as cnt_list

结果：

cnt_list
----------
2 1 1 1 1 

info_message
--------------------------------------------------------------------
There are 2 person(s) with a type of 1(The first column value is: 2)
There are 1 person(s) with a type of 2(The first column value is: 1)
There are 1 person(s) with a type of 3(The first column value is: 1)
There are 1 person(s) with a type of 4(The first column value is: 1)
There are 1 person(s) with a type of 5(The first column value is: 1)

第二部分：

SELECT 'There are ' + CAST(COUNT(*) AS VARCHAR(10)) + ' person(s) with a type of ' + CAST([type] AS VARCHAR(10)) + '(The first column value is: ' + CAST(COUNT(*) AS VARCHAR(10)) + ')' info_message
FROM Person
GROUP BY [Type]

结果：

cnt_list
----------
2 1 1 1 1 

info_message
--------------------------------------------------------------------
There are 2 person(s) with a type of 1(The first column value is: 2)
There are 1 person(s) with a type of 2(The first column value is: 1)
There are 1 person(s) with a type of 3(The first column value is: 1)
There are 1 person(s) with a type of 4(The first column value is: 1)
There are 1 person(s) with a type of 5(The first column value is: 1)

---

我想您是在询问PIVOT查询。类型是否限制为5个选项，或者是n？如果n那么如果有限，那么您就不必使用动态SQL，下面的一种情况也可以使用，或者使用标准pivot。您可以使用STUFF函数而不是varchar（max）来删除xml标记，

SELECT STUFF（（

Your statement here

），1，1，，）)

是的，我以前使用过xml，但我不确定OP想要什么，所以我认为变量是最通用的。