SQLite join命令4表_Sql_Database_Sqlite_Join

SQLite join命令4表

sql database sqlite join

SQLite join命令4表,sql,database,sqlite,join,Sql,Database,Sqlite,Join,我是sql方面的新手，我需要一些帮助。我有3-4个表，我想使用sqlite命令返回一些行。表如下餐桌：餐厅 | Name | menuID | REFERENCES [Menu]([menuID])| | IngredientID | Name | | FoodIncIngredientID | FoodID REFERENCES [Food][FoodID] | IngredientID REFERENCES [Ingredient]([IngredientID])| 表格：菜单 |

我是sql方面的新手，我需要一些帮助。我有3-4个表，我想使用sqlite命令返回一些行。表如下

餐桌：餐厅

| Name | menuID | REFERENCES [Menu]([menuID])|

| IngredientID | Name |

| FoodIncIngredientID | FoodID REFERENCES [Food][FoodID] | IngredientID REFERENCES [Ingredient]([IngredientID])|

表格：菜单

| MenuID | Name |

表格：配料

| Name | menuID | REFERENCES [Menu]([menuID])|

| IngredientID | Name |

| FoodIncIngredientID | FoodID REFERENCES [Food][FoodID] | IngredientID REFERENCES [Ingredient]([IngredientID])|

餐桌：包括配料在内的食品

| Name | menuID | REFERENCES [Menu]([menuID])|

| IngredientID | Name |

| FoodIncIngredientID | FoodID REFERENCES [Food][FoodID] | IngredientID REFERENCES [Ingredient]([IngredientID])|
餐桌：食物

| FoodID | Name | Type | MenuID REFERENCES [Menu][MenuID]|
我想查询一下，如果他们没有我要说的配料，我会返回餐馆的名称、食物名称和食物类型。多谢各位
餐桌餐厅：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter
表格菜单：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter
餐桌食品：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter
餐桌食品，包括配料：

| FoodInclIngredientID | FoodID | IngredientID | 1 29 1 6 31 1 8 30 1
餐桌配料：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter
SQL查询：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter
预期结果：

| Name | MenuId | Goodys 2 Koumbaris 1

| MenuID | Name | 1 koumbarisMenu 2 goodysMenu

| FoodID | Name | Type | MenuID | 29 Chef's Salad Starter 2 31 Mama's Salad Starter 2 30 Ceasar's Salad Starter 2

| IngredientID | Name | 1 Cereals 2 Shellfish

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant INNER JOIN Menu ON Restaurant.menuID = Menu.MenuID INNER JOIN Food ON Menu.MenuID = Food.MenuID INNER JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodID INNER JOIN Ingredient ON Food_Incl_ingredient.FoodInclIngredientID = Ingredient.IngredientID WHERE Ingredient.Name == 'Cereals'

| Name | Name | Type | Goodys Chef's Salad Starter Goodys Mama's Salad Starter Goodys Ceasar's Salad Starter

我得到的唯一结果是第一行。
问题出在哪里？只需连接所有需要的表，然后说
WHERE-component.Name！='肉“

SELECT Restaurant.Name, Food.Name, Food.Type FROM Restaurant JOIN Menu ON Restaurant.menuID = Menu.MenuID JOIN Food ON Menu.MenuID = Food.MenuID JOIN Food_Incl_ingredient ON Food.FoodID = Food_Incl_ingredient.FoodIncIngredientID JOIN Ingredient ON Food_Incl_ingredient.FoodIncIngredientID = Ingredient.Ingredient.ID WHERE Ingredient.Name != 'meat'

我希望我理解了你帖子中的表名和主键；）

…如果他们没有这种成分，我会说
这里有一个非常基本的结构，可以让您编写一个查询，说明餐厅是否需要为其菜单购买配料
你通常会安排一些事情，这样一家餐厅就可以有不止一份菜单，例如早餐、午餐、晚餐，可能还有餐饮或派对
请注意左连接和在最末端使用COALESCE

Restaurant id restaurantname Menu id menuname e.g. Breakfast, Lunch, Dinner, Catering, Party, Special Cultural Holiday Dish id dishname Ingredient id ingredientname
--一道菜有一种或多种配料

Dish_Ingredients dishid ingredientid
--菜单上有一道或多道菜

MenuDish menuid dishid
--餐厅有一个或多个菜单

RestaurantMenu restaurantid menuid
--餐馆备有配料清单

RestaurantIngredients restaurantid ingredientid quantityOnHand
--左连接将导致当菜肴调用库存中没有记录的配料时返回空值；因此，合并（）

自从你说你是新来的，我就听说过这本书的好东西，在10分钟内自学SQL。学习基础知识可以避免很多的摸索。关于没有一个InCredit的部分是不清楚的。也展示一些你这边的努力。如果你也在解决这个问题，人们会在这里寻求帮助。这是一个愚蠢的；）。。。请看查询的第6行。您正在加入食品中包含配料的
。食品中包含配料的。但是您应该加入食品中包含配料的。食品中包含配料的。。还有一个小提示：在最后一行中使用= ，而不是= .OMG！真不敢相信！谢谢,非常感谢。我简直不敢相信我竟然没看到它。：）谢谢你的帮助。奇怪的是为什么它只给我一种食物。数据库中至少有10种食物含有我所吃的谷类配料。我已经让它和谷类食品一样，在你的问题中，看起来你想要所有的餐厅+食物+类型，但没有配料。。。我的问题是给你所有不含肉的食物；）因此，如果你不想吃所有含肉的食物，你必须用= 而不是=在最后一行。是的，我有put==put不正确。它只会给我返回一家有食物的餐厅，而不是10家，例如，其中包含麦片和另一个问题，为什么我们选择餐厅而不是其他桌子？基本上你可以从中选择你想要的。我只想指出一个清晰的JOIN 结构：餐厅->菜单->食品->食品包含配料->配料。理解这个复杂的查询有点困难，但我会尝试处理这是什么，谢谢。这真的不是一个复杂的查询。这是同一类型的简单连接，在多个表中多次发生，仅此而已。一旦你理解了“链接”菜单和餐具配料表的目的，一切都会变得清晰起来。