Sql 在oracle中按小时计算两个日期之间的记录数

我需要在oracle中执行此序列的单个查询

select count(*) from table1
where request_time < timestamp'2012-05-19 12:00:00' and (end_time > timestamp'2012-05-19 12:00:00' or end_time=null);

select count(*) from table1
where request_time < timestamp'2012-05-19 13:00:00' and (end_time > timestamp'2012-05-19 13:00:00' or end_time=null);

select count(*) from table1
where request_time < timestamp'2012-05-19 14:00:00' and (end_time > timestamp'2012-05-19 14:00:00' or end_time=null);

select count(*) table1
where request_time < timestamp'2012-05-19 15:00:00' and (end_time > timestamp'2012-05-19 15:00:00' or end_time=null);

select count(*) from table1
where request_time < timestamp'2012-05-19 16:00:00' and (end_time > timestamp'2012-05-19 16:00:00' or end_time=null);

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我写了一个问题，但它没有给我正确的答案

select col1, count(*) from
(select TO_CHAR(request_time, 'YYYY-MM-DD HH24') as col1 from table1
 where request_time <= timestamp'2012-05-19 12:00:00' and (end_time >= timestamp'2012-05-19 12:00:00' or end_time=null))
group by col1 order by col1;

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您的单个查询似乎与重叠的记录集相匹配。如果你在你的问题中加入一些样本数据，这会有所帮助，但我可以猜

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例如，第一次查询和第二次查询都将统计所有结束时间为null、请求时间为2012-05-19 13:30:00的记录；但在“总体”查询中，它们只计算一次

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也许您想查询请求时间的日期范围，而不是像

request\u time

？

注意

trunc

表达式与日期值的用法。如果您没有在sql*plus中运行查询，则可以省略

alter session

SQL> alter session set nls_date_format='yyyy-mm-dd hh24:mi:ss';

Session altered.

SQL> SELECT 
       trunc(created,'HH'), 
       count(*) 
     FROM 
       test_table 
     WHERE 
       created > trunc(SYSDATE -2) 
     group by trunc(created,'HH');


TRUNC(CREATED,'HH')   COUNT(*)
------------------- ----------
2012-05-21 09:00:00        748
2012-05-21 16:00:00         24
2012-05-21 17:00:00         12
2012-05-21 22:00:00        737
2012-05-21 23:00:00        182
2012-05-22 20:00:00         16
2012-05-22 21:00:00        293
2012-05-22 22:00:00        610

8 ROWS selected.

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对于Oracle数据库，其工作正常

挑选 至_char（已更新，'DD-MM-YYYY HH'）， 计数（*） 从…起 顾客 哪里 trunc（更新）>=至_Char（'2017年7月2日' 和trunc（更新）试试这个

select TO_CHAR(request_time, 'HH24') as "hourOfDay",count(*)as
"numOfLogin", TO_CHAR(request_time, 'DD') as "date" from table1 
where request_time<= timestamp'2017-08-04 23:59:59' and
(request_time>= timestamp'2017-08-03 00:00:01' ) group by
TO_CHAR(request_time, 'HH24'),TO_CHAR(request_time, 'DD');

选择将字符（请求时间，'HH24'）作为“hourOfDay”，将（*）作为
“numOfLogin”，将表1中的字符（请求时间，'DD'）作为“日期”
其中请求时间=时间戳'2017-08-03 00:00:01'）分组人
TO_CHAR（请求时间，'HH24'）、TO_CHAR（请求时间，'DD'）；

“将由第一个和第二个查询计算”是的，我需要这个。像斐波那契！这个小时的计数是前几个小时的计数+这个小时的计数。我有两个日期，我想在两个日期之间计算这个查询。然后我想扩展这个查询，以按天、月甚至年获得结果！谢谢，但这给了我同样的结果，我写的小组。问题是：我需要22:00:00小时的总和，在你的例子中是748+24+12+737+182+16+293+610=2622，而16:00:00小时应该是748+24=772，依此类推……我想我不明白你的意思。@Heidarzadeh：如果你说的是运行

COUNT（*）的总和

，请用

COUNT（*）试试ipip的解决方案

替换为

sum（count（*）over（order by trunc（created，'HH'））

@Andriy M我尝试了您的解决方案，但得到了这个错误“没有一个单独的组函数”@Heidarzadeh:您确定

trunc（created，'HH'）

仍然包含在

group by

中吗？

COUNT(*)               
1322                   

COUNT(*)               
1237

select col1, count(*) from
(select TO_CHAR(request_time, 'YYYY-MM-DD HH24') as col1 from table1
 where request_time <= timestamp'2012-05-19 12:00:00' and (end_time >= timestamp'2012-05-19 12:00:00' or end_time=null))
group by col1 order by col1;

COL1          COUNT(*)               
------------- ---------------------- 
2012-05-19 07      22                     
2012-05-19 08      141                    
2012-05-19 09      322                    
2012-05-19 10      318                    
2012-05-19 11      282  

SQL> alter session set nls_date_format='yyyy-mm-dd hh24:mi:ss';

Session altered.

SQL> SELECT 
       trunc(created,'HH'), 
       count(*) 
     FROM 
       test_table 
     WHERE 
       created > trunc(SYSDATE -2) 
     group by trunc(created,'HH');


TRUNC(CREATED,'HH')   COUNT(*)
------------------- ----------
2012-05-21 09:00:00        748
2012-05-21 16:00:00         24
2012-05-21 17:00:00         12
2012-05-21 22:00:00        737
2012-05-21 23:00:00        182
2012-05-22 20:00:00         16
2012-05-22 21:00:00        293
2012-05-22 22:00:00        610

8 ROWS selected.

select TO_CHAR(request_time, 'HH24') as "hourOfDay",count(*)as
"numOfLogin", TO_CHAR(request_time, 'DD') as "date" from table1 
where request_time<= timestamp'2017-08-04 23:59:59' and
(request_time>= timestamp'2017-08-03 00:00:01' ) group by
TO_CHAR(request_time, 'HH24'),TO_CHAR(request_time, 'DD');